請問大神，比如以下日志資訊：
2020-10-24 01:55:28.415:
aaaaaaaaaa
2020-10-25 01:55:28.415:
bbbbbbbbbb
2020-10-26 01:55:28.415:
cccccccccc
2020-10-26 01:55:28.415:
[ctssd(6797)]CRS-2408:The clock on host
2020-10-26 02:26:24.702:
[ctssd(6797)]CRS-2408:The clock on host
2020-10-26 02:59:20.981:
[ctssd(6797)]CRS-2408:The clock on host
2020-10-26 03:32:33.281:
[ctssd(6797)]CRS-2408:The clock on host
2020-10-26 04:05:53.588:
[ctssd(6797)]CRS-2408:The clock on host
2020-10-26 04:39:13.904:
[ctssd(6797)]CRS-2408:The clock on host
查看日志檔案時，要將含“CRS-2408”的行以及上面一行日期過濾掉，只剩下：
2020-10-24 01:55:28.415:
aaaaaaaaaa
2020-10-25 01:55:28.415:
bbbbbbbbbb
2020-10-26 01:55:28.415:
cccccccccc
要怎么實作
uj5u.com熱心網友回復：
sed 'N;/\n.*CRS*/!P;D' logfile | grep -v CRS轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/192850.html
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