來自DB檔案值的DjangoURL路徑

我正在嘗試創建使用 {{ project.title }} 值生成路徑的“專案”頁面，而不是我使用整數的當前方法。我不太明白我怎么能做到這一點，但覺得我很接近？

模型.py

from django.db import models

# Create your models here.
class Project(models.Model):
    title = models.CharField(max_length=100)
    description = models.TextField()
    technology = models.CharField(max_length=20)
    image = models.FilePathField(path='projects/static/img/')
    live = models.URLField()
    source = models.URLField()

    def __str__(self):
        return self.title

網址.py

from django.urls import path
from . import views

urlpatterns = [
    path("", views.project_index, name="projects"),
    path("<int:pk>/", views.project_details, name="project_details"),  # PK for Primary Key
]

視圖.py

from django.shortcuts import render
from .models import Project

# Create your views here.
def project_index(request):
    projects = Project.objects.all()
    context = {'projects': projects}
    return render(request, 'projects/project_index.html', context)

def project_details(request, pk):
    project = Project.objects.get(pk=pk)
    context = {'project': project}
    return render(request, 'projects/project_details.html', context)

我認為path("<int:pk>/",需要成為一個蛞蝓，但我無法弄清楚如何系結資料庫資料。可能context = {'project': project}嗎？

目前網址是http://127.0.0.1:8000/projects/1/ - 我正在尋找http://127.0.0.1:8000/projects/EXAMPLE/

謝謝

uj5u.com熱心網友回復：

網址.py

    path("<title>/", views.project_details, name="project_details"),

視圖.py

from django.shortcuts import get_object_or_404
def project_details(request, title: str):
    project = get_object_or_404(Project, title=title)

uj5u.com熱心網友回復：

您必須SlugField在models.py檔案中添加一個：

模型.py

from django.db import models
from django.utils.text import slugify

# Create your models here.
class Project(models.Model):
    title = models.CharField(max_length=100)
    description = models.TextField()
    technology = models.CharField(max_length=20)
    image = models.FilePathField(path='projects/static/img/')
    live = models.URLField()
    source = models.URLField()
    slug = models.SlugField(default="", blank=True, null=False, db_index=True)

    def __str__(self):
        return self.title

    def save(self, *args, **kwargs):
        self.slug = slugify(self.title)
        super().save(*args, **kwargs)

視圖.py

from django.shortcuts import render
from .models import Project

# Create your views here.
def project_index(request):
    projects = Project.objects.all()
    context = {'projects': projects}
    return render(request, 'projects/project_index.html', context)

def project_details(request, slug):
    project = Project.objects.get(slug=slug)
    context = {'project': project}
    return render(request, 'projects/project_details.html', context)

網址.py

from django.urls import path
from . import views

urlpatterns = [
    path("", views.project_index, name="projects"),
    path("<slug:slug>/", views.project_details, name="project_details"),
]

確保運行makemigrations然后migrate。

標籤：Python 姜戈 django-views django-模板

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