我想從字串串列中洗掉重復的子字串。*假設每個串列的重復子串不同。
例子：
lst = ['State your favorite fruit: Apple', 'State your favorite fruit: Orange', 'State your favorite fruit: Grapes']
期望的結果：
final_lst = ['Apple', 'Orange', 'Grapes']
編輯：對不起，如果我最初的問題不清楚。我希望從每個字串串列中找到唯一的單詞。
lst1 = ['This is a bag', 'This is a cat', 'This is a dog']
lst2 = ['Favorite drink: Cola', 'Favorite drink: Sprite']
lst3 = ['My name is James', 'My name is Mary Jane', 'My name is Lopez']
期望的輸出：
final_lst1 = ['bag', 'cat', 'dog']
final_lst2 = ['Cola', 'Sprite']
final_lst3 = ['James', 'Mary Jane', 'Lopez']
uj5u.com熱心網友回復：
可能還有其他某些方法可以做到這一點，但下面的方法非常適合此目的
所以，你的清單如下：
lst = ['State your favorite fruit: Apple', 'State your favorite fruit: Orange', 'State your favorite fruit: Grapes']
現在，將所有單詞分成一個新串列
seperate_words = (" ".join(lst)).split(" ") #First we join all the sentences of the list
# with a space in between using the "join" method of string.
#Then consequently splitting the list by a space
最后，要獲得唯一的單詞，請使用如下串列理解
unique_words = [word for word in seperate_words if seperate_words.count(word) == 1]
print(unique_words)
輸出：['蘋果'，'橙色'，'葡萄']
問候
uj5u.com熱心網友回復：
這是所問問題的解決方案：
final_lst = [s.replace('State your favorite fruit: ') for s in lst]
uj5u.com熱心網友回復：
只需使用串列理解：
lst = ['State your favorite fruit: Apple', 'State your favorite fruit: Orange', 'State your favorite fruit: Grapes']
final_lst = [s.replace('State your favorite fruit: ', '') for s in lst]
print(final_lst)
輸出：
['Apple', 'Cherry', 'Grapes']
uj5u.com熱心網友回復：
您可以拆分“：”并獲得如下所示的最后一個索引：
[x.split(":")[-1] for x in lst]
uj5u.com熱心網友回復：
您可以遍歷串列，然后從每個字串中取出最后一個單詞：
final_lst = [w.split(" ")[-1] for w in lst]
轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/323933.html