我有一個這樣的陣列：
array = [
{
"title": "a",
"date": "2021-10-25T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-20T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-28T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-30T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-26T18:00:00.000"
}
]
我想先用最近的物件對它進行排序。我嘗試排序，但我認為，我沒有這樣做的好方法。
這是我試過的：
array.sort((a, b) => {
return (new Date(b.battle_start) > new Date()) - (new Date(a.battle_start) < new Date())
})
這就是我想要的
array = [
{
"title": "b",
"date": "2021-10-26T18:00:00.000"
},
{
"title": "a",
"date": "2021-10-25T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-28T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-30T18:00:00.000"
},
{
"title": "b",
"date": "2021-10-20T18:00:00.000"
}
]
uj5u.com熱心網友回復：
您的代碼可以適用于使用Math.abs，以便以相同的方式看待與過去或未來的距離：
const array = [{"title": "a","date": "2021-10-25T18:00:00.000"},{"title": "b","date": "2021-10-20T18:00:00.000"},{"title": "b","date": "2021-10-28T18:00:00.000"},{"title": "b","date": "2021-10-30T18:00:00.000"},{"title": "b","date": "2021-10-26T18:00:00.000"}];
let now = Date.now();
array.sort((a,b) =>
Math.abs(Date.parse(a.date) - now) - Math.abs(Date.parse(b.date) - now)
);
console.log(array);uj5u.com熱心網友回復：
您應該能夠通過以下方式做到這一點：
array.sort((a, b) => {
return (Math.abs(new Date(a.battle_start) - new Date())) - Math.abs((new Date(b.battle_start) - new Date()))
})
您要比較的是“現在”和目標日期之間的距離。
轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/348066.html
標籤：javascript 数组 日期 排序