如何找到嵌套在陣列中的物件鍵的差異-有解無憂

我有 3 個物件，它們有一個“成本”鍵，它是物件陣列。結果，我想要一個“主”，它會保持不變，除了它的“值”將是這個值減去其他物件“值”的差異

const main = {
  cost: [
    { id: 'main', value: 20, timestapm: 'asd', current: '10'},
    { id: 'main', value: 10, timestapm: 'asd', current: '10'},
    { id: 'main', value: 18, timestapm: 'asd', current: '10'},
  ],
  description: 'maindevice',
  total: 5
}

const other = {
  cost: [
    { id: 'device1', value: 10, timestapm: 'qwe', current: '10'},
    { id: 'device1', value: 5, timestapm: 'qwe', current: '10'},
    { id: 'device1', value: 9, timestapm: 'qwe', current: '10'},
  ],
  description: 'maindevice',
  total: 3
}

const other2 = {
  cost: [
    { id: 'device2', value: 5, timestapm: 'zxc', current: '10'},
    { id: 'device2', value: 2, timestapm: 'zxc', current: '10'},
    { id: 'device2', value: 2, timestapm: 'zxc', current: '10'},
  ],
  description: 'maindevice',
  total: 6
}

const devices = [main, other, other2];

result i want to have => 

main = {
  cost: [
    { id: 'main', value: 5, timestapm: 'asd', current: '10'},
    { id: 'main', value: 3, timestapm: 'asd', current: '10'},
    { id: 'main', value: 7, timestapm: 'asd', current: '10'},
  ],
  description: 'maindevice',
  total: 5
}

uj5u.com熱心網友回復：

const calcNewValue = (main, other, other2) => {
    main.cost = main.cost.map((obj, index) => { return {...obj, value: value=other.cost[index].value - other2.cost[index].value}})
    return main
}

這對你有用

uj5u.com熱心網友回復：

您可以減少devices和改變陣列的第一個物件。

const
    main = { cost: [{ id: 'main', value: 20, timestamp: 'asd', current: '10'}, { id: 'main', value: 10, timestapm: 'asd', current: '10'}, { id: 'main', value: 18, timestapm: 'asd', current: '10'}], description: 'maindevice', total: 5 },
    other = { cost: [{ id: 'device1', value: 10, timestamp: 'qwe', current: '10'}, { id: 'device1', value: 5, timestapm: 'qwe', current: '10'}, { id: 'device1', value: 9, timestapm: 'qwe', current: '10'}], description: 'maindevice', total: 3 },
    other2 = { cost: [{ id: 'device2', value: 5, timestamp: 'zxc', current: '10'}, { id: 'device2', value: 2, timestapm: 'zxc', current: '10'}, { id: 'device2', value: 2, timestapm: 'zxc', current: '10'}], description: 'maindevice', total: 6 },
    devices = [main, other, other2];

devices.reduce((r, o) => {
    o.cost.forEach(({ value }, i) => r.cost[i].value -= value);
    return r;
});

console.log(main);

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