我正在嘗試嵌套兩個字典，也許只制作一個字典更容易，但是，我有具有不同值的相同鍵，只是更改鍵更容易還是有辦法嵌套這兩個？
Number_As = 1
#DNA dictionary
DNAdict = {
'A': ['dAMP',1,..., other values],
'C': ['dCMP',2,..., other values],
'T': ['dTMP',3,..., other values],
'G': ['dGMP',4,..., other values]}
#RNA dictionary
RNAdict = {
'A': ['AMP',5,..., other values],
'C': ['CMP',6,..., other values],
'U': ['UMP',7,..., other values],
'G': ['GMP',8,..., other values]}
然后我嘗試訪問不同計算的各個值：
Energy of DNA_A = Number_As * DNAdict['A'][1]
Energy of DNA_A = 1
or
Energy of RNA_A = Number_As * RNAdict['A'][1]
Energy of RNA_A = 5
但我只想擁有一本字典，然后盡管名稱相同，但仍可以訪問每個鍵的不同值。是否可以？
非常感謝！！
uj5u.com熱心網友回復：
你怎么知道你現在想使用哪個字典？如果您想在當前狀態下對 dict 的各個元素保持很少的控制（例如，['dAMP',1,..., other values]您可以使 dict 的值成為串列串列并通過索引參考所需的元素。但是，如果您可以分配每個元素都有一個唯一的名稱，實際上您可以使用以下代碼創建一個嵌套的字典：
# Your current code goes here
acids = {'DNA': RNAdict, 'DNA': DNAdict}
# Then you can access a specific dict by
dna_a_energy = Number_As * acids['DNA']['A'][1]
rna_a_energy = Number_As * acids['RNA']['A'][1]
如果我理解正確的話。
uj5u.com熱心網友回復：
是的，所有的可能性，它都有可能
1：硬編碼：
grouped = {
'DNAdict':{
'A': ['dAMP',1,..., ],
'C': ['dCMP',2,..., ],
'T': ['dTMP',3,..., ],
'G': ['dGMP',4,..., ]},
'RNAdict':{
'A': ['AMP',5,..., ],
'C': ['CMP',6,..., ],
'U': ['UMP',7,..., ],
'G': ['GMP',8,..., ]}
}
#acessing RNAdict a[0]
value = grouped['RNAdict']['A'][0]
print(value)
2：按代碼分組
#RNA dictionary
DNAdict = {
'A': ['dAMP',1,..., ],
'C': ['dCMP',2,..., ],
'T': ['dTMP',3,..., ],
'G': ['dGMP',4,..., ]}
#RNA dictionary
RNAdict = {
'A': ['AMP',5,..., ],
'C': ['CMP',6,..., ],
'U': ['UMP',7,..., ],
'G': ['GMP',8,..., ]}
grouped = {'DNAdict':DNAdict,'RNAdict':RNAdict}
#example of finding
value = grouped['RNAdict']['A'][0]
print(value)
3 添加前綴：
def add_prefix(elem:dict,prefix:str)->dict:
new_dict = {}
for key in elem.keys():
new_dict[f'{prefix}_{key}'] = elem[key]
return new_dict
DNAdict = {
'A': ['dAMP',1,..., ],
'C': ['dCMP',2,..., ],
'T': ['dTMP',3,..., ],
'G': ['dGMP',4,..., ]}
#RNA dictionary
RNAdict = {
'A': ['AMP',5,..., ],
'C': ['CMP',6,..., ],
'U': ['UMP',7,..., ],
'G': ['GMP',8,..., ]}
Dna = add_prefix(elem=DNAdict,prefix='DNA')
Rna = add_prefix(elem=RNAdict,prefix='RNA')
Nested= {**Dna, **Rna}
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