如何根據父類中的名稱動態設定屬性？

如何將每個 AlarmModel 的“名稱”屬性動態設定為父類中的模型名稱（即 HardwareFault）？

public class NotificationModel
{
    public string UnrelatedProperty { get; set; }  // any solution should ignore other properties.

    public AlarmModel HardwareFault{ get; set; }

    public AlarmModel TimeoutFault { get; set; }

    public AlarmModel GenericFault { get; set; }
}

public class AlarmModel
{
    public string Name { get; set; }

    public bool isActive { get; set; }

    public bool isEnabled { get; set; }

    public bool isSilenced { get; set; }
}

uj5u.com熱心網友回復：

您應該將屬性“名稱”移至父類。并嘗試將其擴展/繼承到子類。

uj5u.com熱心網友回復：

如果您已經 NotificationModel使用也已初始化的HardwareFault, TimeoutFault,GenericFault屬性進行了初始化，則可以使用以下示例：

var notificationModel = new NotificationModel()
{
    HardwareFault = new AlarmModel(),
    GenericFault = new AlarmModel(),
    TimeoutFault = new AlarmModel()
};

notificationModel?.GetType().GetProperties().Where(p => p.PropertyType.Name == "AlarmModel") // Or p.PropertyType == typeof(AlarmModel)
                                            .ToList().ForEach(alarmModelProperty =>
{
    // Get AlarmModel property instance
    var alarmModelInstance = alarmModelProperty.GetValue(notificationModel);
    // Get Name property
    var nameProperty = alarmModelIntance?.GetType().GetProperty("Name");
    // Set Name property value with name of AlarmModel property
    nameProperty?.SetValue(alarmModelInstance, alarmModelProperty.Name);
});

如果您已經初始化 NotificationModel, 但沒有初始化HardwareFault, TimeoutFault,GenericFault屬性，您可以使用以下示例：

var notificationModel = new NotificationModel();

notificationModel?.GetType().GetProperties().Where(p => p.PropertyType.Name == "AlarmModel") // Or p.PropertyType == typeof(AlarmModel)
                                            .ToList().ForEach(alarmModelProperty =>
{
    // Initialize new AlarmModel 
    var alarmModelInstance = Activator.CreateInstance(alarmModelProperty.PropertyType);
    // Get Name property of AlarmModel
    var nameProperty = alarmModelInstance.GetType().GetProperty("Name");
    // Set Name property of AlarmModel
    nameProperty?.SetValue(alarmModelInstance, alarmModelProperty.Name);
    // Set AlarmModel property of NotificationModel
    alarmModelProperty.SetValue(notificationModel, alarmModelInstance);
});

如果您需要使用反射進行完全初始化，您可以使用以下示例：

var notificationModelType = Assembly.GetExecutingAssembly().GetTypes().FirstOrDefault(type => type.Name == "NotificationModel"); // Or type == typeof(NotificationModel)
if (notificationModelType is null) // No NotificationModel found in current assembly
    return;

// Initializing NotificationModel
var notificationModel = Activator.CreateInstance(notificationModelType);

notificationModel?.GetType().GetProperties().Where(p => p.PropertyType.Name == "AlarmModel") // Or p.PropertyType == typeof(AlarmModel)
                                            .ToList().ForEach(alarmModelProperty =>
{
    // Initialize new AlarmModel 
    var alarmModelInstance = Activator.CreateInstance(alarmModelProperty.PropertyType);
    // Get Name property of AlarmModel
    var nameProperty = alarmModelInstance.GetType().GetProperty("Name");
    // Set Name property of AlarmModel
    nameProperty?.SetValue(alarmModelInstance, alarmModelProperty.Name);
    // Set AlarmModel property of NotificationModel
    alarmModelProperty.SetValue(notificationModel, alarmModelInstance);
});

如果NotificationModel在當前程式集中宣告 NOT （因此它不會在 中Assembly.GetExecutingAssembly().GetTypes()） - 您可以在 中搜索所有加載的程式集AppDomain.CurrentDomain：

var notificationModelType = AppDomain.CurrentDomain.GetAssemblies()
                                                   .SelectMany(assembly => assembly.GetTypes())
                                                   .FirstOrDefault(type => type.Name == "NotificationModel");

uj5u.com熱心網友回復：

如果我理解正確，您想將Name每個AlarmModel的屬性設定為父級中的屬性名稱NotificationModel嗎？

如果是這種情況，您可以執行以下操作：

public class NotificationModel
{
    private AlarmModel _hardwareFault;

    private AlarmModel _timeoutFault;

    private AlarmModel _genericFault;

    public string UnrelatedProperty { get; set; }  // any solution should ignore other properties.

    public AlarmModel HardwareFault
    { 
        get => _hardwareFault; 
        set
        {
            _hardwareFault = value;
            SetName(value);
        }
    }

    public AlarmModel TimeoutFault 
    {
        get => _timeoutFault; 
        set
        {
            _timeoutFault= value;
            SetName(value);
        }
    }

    public AlarmModel GenericFault 
    {
        get => _genericFault; 
        set
        {
            _genericFault= value;
            SetName(value);
        }
    }

    private void SetName(AlarmModel model, [CallerMemberName] string propertyName = null)
    {
        model.Name = propertyName;
    }
}

標籤：C＃ 林克 班级 反射

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