Java：計算陣列中的對

我試圖構建一個小游戲，隨機生成一個 10、20、50、200、1000 的陣列。它計算一定數量的對，但是它以某種奇怪的方式計算。如果我有 10 個中的 3 個，則計算為 2 對，如果我有 10 個中的 4 個，則計算為 5 對。基本上，我只需要如果它是 10 個中的 4 個，那么它應該有 2 對，如果它是 10 個中的 6 個，則它應該有 3 對。任何提示，建議表示贊賞

int[] bonusGame = new int[5]; // bonus game array
int bonusGameSum=0; // amount of prize for bonus game 
int randomChance = r.nextInt(100); // generating chance
for (int newNum = 0; newNum<5 ;newNum  ) { // getting chances for numbers
    int chanceGen = r.nextInt(100); // generating chance 
    if (chanceGen <= 50) { // generating chance for 10 
        bonusGame[newNum] = 10;
    }
    else if (chanceGen <= 77) { // generating chance for 20
        bonusGame[newNum] = 20;
    }
    else if (chanceGen <= 92) { // generating chance for 50 
        bonusGame[newNum] = 50;
    }
    else if (chanceGen <= 98) { // generating chance for 200 
        bonusGame[newNum] = 200;
    }
    else {                       // generating chance for 1000
        bonusGame[newNum] = 1000;
    }
    
    }
for (int z: bonusGame) {
    System.out.println(z);
}
for (int f = 0; f < bonusGame.length - 1;   f) { // checking for pairs in array and adding up to winning sum
    for (int j = f   1; j < bonusGame.length;   j) {
        if (bonusGame[j] == bonusGame[f] & bonusGame[j] == 10 ) { // if 10 has pairs
            System.out.println(" You won 10 euro ");
            bonusGameSum  =10;
        }
        else if (bonusGame[j] == bonusGame[f] & bonusGame[j] == 20 ) { // if 20 has pairs
            System.out.println(" You won 20 euro ");
            bonusGameSum  =20;
        }
        else if (bonusGame[j] == bonusGame[f] & bonusGame[j] == 50 ) { // if 50 has pairs
            System.out.println(" You won 50 euro ");
            bonusGameSum  =50;
        }
        else if (bonusGame[j] == bonusGame[f] & bonusGame[j] == 200 ) { // if 200 has pairs
            System.out.println(" You won 200 euro ");
            bonusGameSum  =200;
        }
        else if (bonusGame[j] == bonusGame[f] & bonusGame[j] == 1000 ) { // if 1000 has pairs
            System.out.println(" You won 1000 euro ");
            bonusGameSum  =1000;
        }
    }

}

uj5u.com熱心網友回復：

您的程式會計算相同值在串列中出現的次數。

為了實作您的意圖，您可以嘗試不同的方法，例如：

1 創建已使用號碼串列

2 使用“陣列串列”洗掉已使用的值或將它們更改為 0

3 創建每個結果的出現串列

我在下面介紹方法 3：

    Random r = new Random();
    int[] bonusGame = new int[5]; // bonus game array


    for (int newNum = 0; newNum < bonusGame.length; newNum  )
    { // getting chances for numbers
        int chanceGen = r.nextInt(100); // generating chance

        if (chanceGen <= 50)
        { // generating chance for 10
            bonusGame[newNum] = 10;
        }
        else if (chanceGen <= 77)
        { // generating chance for 20
            bonusGame[newNum] = 20;
        }
        else if (chanceGen <= 92)
        { // generating chance for 50
            bonusGame[newNum] = 50;
        }
        else if (chanceGen <= 98)
        { // generating chance for 200
            bonusGame[newNum] = 200;
        }
        else
        { // generating chance for 1000
            bonusGame[newNum] = 1000;
        }
    }

    for (int z: bonusGame)
    {
        System.out.println(z);
    }

    int[] pool = {10, 20, 50, 200, 1000}; // possible winnings
    int[] pairs = {0, 0, 0, 0, 0}; // array counting how many times we scored each number
    for (int value : bonusGame)  // search through random results
    {
        int index = 0; // matching random result with correct element of the pool
        for (int size : pool) // comparing each result with our possible winnings
        {
            if (value == size)
            {
                pairs[index]  ; // increase number of successes by one
                break;
            }
            index  ;
        }
    }

    int index = 0;
    for (int value : pairs)  // search through created list of values for each random result
    {
        while (value >= 2) // when such result occurred at least twice
        {
            value -= 2;
            System.out.println("You won "   pool[index]   " euro");
        }
        index  ;
    }

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