按日期過濾休息請求的最佳方法是什么？
將作業傳遞一個變數可能是這樣的：
today = date.today() today_90 = today - timedelta(days = 90)
service-now.com/api/now/table/incident?sysparm_limit=1000&sysparm_query=sys_created_on**dates values here?**
uj5u.com熱心網友回復：
我試著理解你的問題：
from datetime import date, timedelta
import requests
today = date.today()
today_90 = today - timedelta(days = 90)
r = requests.get('https://xxxx.service-now.com/api/now/table/incident?sysparm_limit=1000&sysparm_query=sys_created_on>' str(today_90) '&sysparm_query=sys_created_on<' str(today))
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