根據運氣選擇正確的專案Lua

假設我有這張桌子。

Config.LootboxesRewards = {
    [1] = {
        {name = 'a45amg',               label = 'Mercedes A45 AMG ',    amount = 1,     type = 'car',   luck = 3},
        {name = '720s',                 label = '720s mclaren',         amount = 1,     type = 'car',   luck = 20},
        {name = 'bac2',                 label = 'bac2',                 amount = 1,     type = 'car',   luck = 20},
        {name = 'm6prior',              label = 'BMW M6',               amount = 1,     type = 'car',   luck = 19},
        {name = 'huracan',              label = 'Lamborghini Huracan',  amount = 1,     type = 'car',   luck = 19},
        {name = 'yzfr6',                label = 'Yamaha R6',            amount = 1,     type = 'car',   luck = 19},
    },
} 

基于此，我想根據該表上的運氣值給玩家 1 個專案。最好的方法是什么？

uj5u.com熱心網友回復：

最簡單的方法是將指數Config.LootboxesRewards[1]帶math.random(#Config.LootboxesRewards[1])

這假設您只想給您的玩家一個均勻分布的隨機專案。如果你想改變獲得特定物品的機會，我建議你從這里開始：

https://en.wikipedia.org/wiki/Probability

讀：

https://www.lua.org/manual/5.4/manual.html#pdf-math.random

https://www.lua.org/manual/5.4/manual.html#pdf-math.randomseed

uj5u.com熱心網友回復：

一種簡單的解決方案是將具有較高機會（較高運氣值）的值比具有較低變化（較低運氣值）的物品更頻繁地放入戰利品表中。

為了方便起見，您仍然可以保留您的表格并像這樣預處理表格：

local function gcd(a, b)
    while a ~= b do
        if a > b then
            a = a - b
        else
            b = b - a
        end
    end

    return a
end

local function gcd_tbl(values, value_getter)
    if #values < 1 then
        return nil
    end

    value_getter = value_getter or function(v) return v end

    local result = value_getter(values[1])

    for i = 2, #values do
        result = gcd(result, value_getter(values[i]))
    end

    return result
end

local function process_rewards(tbl)
    local result = {}

    for id, rewards in pairs(tbl) do
        result[id] = {}

        local greatest_common_divisor = gcd_tbl(rewards, function(v) return v.luck end)

        for _, reward in ipairs(rewards) do
            for i = 1, reward.luck / greatest_common_divisor do
                table.insert(result[id], reward)
            end
        end
    end

    return result
end

Config.LootboxesRewards = process_rewards({
    [1] = {
        {name = 'a45amg',               label = 'Mercedes A45 AMG ',    amount = 1,     type = 'car',   luck = 3},
        {name = '720s',                 label = '720s mclaren',         amount = 1,     type = 'car',   luck = 20},
        {name = 'bac2',                 label = 'bac2',                 amount = 1,     type = 'car',   luck = 20},
        {name = 'm6prior',              label = 'BMW M6',               amount = 1,     type = 'car',   luck = 19},
        {name = 'huracan',              label = 'Lamborghini Huracan',  amount = 1,     type = 'car',   luck = 19},
        {name = 'yzfr6',                label = 'Yamaha R6',            amount = 1,     type = 'car',   luck = 19},
    }
})

然后，您可以從表中選擇一個隨機索引來查找獎勵：

function get_random_reward(lootbox_id)
    local lootbox_rewards = Config.LootboxesRewards[lootbox_id]
    if not lootbox_rewards then
        return nil
    end

    return lootbox_rewards[math.random(#lootbox_rewards)]
end

get_random_reward(1)

編輯：如果你想表明相反的方式（更高的運氣=更少的機會掉落），你可以使用這兩個功能：

local function gcd_and_max_tbl(values, value_getter)
    if #values < 1 then
        return nil, nil
    end

    value_getter = value_getter or function(v) return v end

    local value = value_getter(values[1])
    local gcd_result, max_result = value, value

    for i = 2, #values do
        value = value_getter(values[i])
        gcd_result = gcd(gcd_result, value)
        max_result = math.max(max_result, value)
    end

    return gcd_result, max_result
end

local function process_rewards(tbl)
    local result = {}

    for id, rewards in pairs(tbl) do
        result[id] = {}

        local greatest_common_divisor, max_luck = gcd_and_max_tbl(rewards, function(v) return v.luck end)
        local max_relevant_luck = max_luck / greatest_common_divisor

        for _, reward in ipairs(rewards) do
            for i = 1, max_relevant_luck - (reward.luck / greatest_common_divisor)   1 do
                table.insert(result[id], reward)
            end
        end
    end

    return result
end

uj5u.com熱心網友回復：

如果運氣只是被選中的可能性，那么運氣為 10 的汽車比運氣為 5 的汽車有兩倍的機會被選中，您可以這樣做

function pickBasedOnLuck(list)
    local totalLuck = 0
    for i, car in ipairs(list) do
        totalLuck = totalLuck   car.luck
    end
    local pick = math.random(totalLuck)
    for i, car in ipairs(list) do
        if pick > car.luck then
            pick = pick - car.luck
        else
            return car
        end
    end
end

所以在你的情況下，它可以被稱為pickBasedOnLuck(Config.LootboxesRewards[1]).

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