googletest中部分有序模擬呼叫的多個先決條件-有解無憂

我讀了googletest部分有序呼叫這里，我understoond如何他們為榜樣的作品。所以我們可以使用：

using ::testing::Sequence;
...
  Sequence s1, s2;

  EXPECT_CALL(foo, A())
      .InSequence(s1, s2);
  EXPECT_CALL(bar, B())
      .InSequence(s1);
  EXPECT_CALL(bar, C())
      .InSequence(s2);
  EXPECT_CALL(foo, D())
      .InSequence(s2);

顯示以下 DAG：

        ---> B
       |
  A ---|
       |
        ---> C ---> D

但我想知道我們如何定義呼叫的多個先決條件。例如，如何E在以下 DAG 中為節點添加 DAG 約束？

        ---> B ---------- 
       |                 |
  A ---|                 |---> E
       |                 |
        ---> C ---> D ---

會是這樣嗎？

using ::testing::Sequence;
...
  Sequence s1, s2, s3;

  EXPECT_CALL(foo, A())
      .InSequence(s1, s2);
  EXPECT_CALL(bar, B())
      .InSequence(s1, s3);
  EXPECT_CALL(bar, C())
      .InSequence(s2);
  EXPECT_CALL(foo, D())
      .InSequence(s2, s3);
  EXPECT_CALL(foo, E())
      .InSequence(s3);

uj5u.com熱心網友回復：

您可以使用 After 方法在某些其他呼叫之后期待一些呼叫。 https://google.github.io/googletest/reference/mocking.html#EXPECT_CALL.After

所以在你的情況下，它會是這樣的：

Mocked mock;
Sequence s1, s2;
EXPECT_CALL(mock, A).InSequence(s1, s2);
Expectation exp_b = EXPECT_CALL(mock, B).InSequence(s1);
EXPECT_CALL(mock, C).InSequence(s2);
Expectation exp_d = EXPECT_CALL(mock, D).InSequence(s2);
EXPECT_CALL(mock, E).After(exp_b, exp_d);

完整的可運行示例：

#include <gmock/gmock.h>
#include <gtest/gtest.h>

using ::testing::Sequence;
using ::testing::Expectation;

class Mocked {
public:
    MOCK_METHOD(void, A, ());
    MOCK_METHOD(void, B, ());
    MOCK_METHOD(void, C, ());
    MOCK_METHOD(void, D, ());
    MOCK_METHOD(void, E, ());
};

TEST(Sequences, ABCDE)
{
    Mocked mock;
    Sequence s1, s2;
    EXPECT_CALL(mock, A).InSequence(s1, s2);
    Expectation exp_b = EXPECT_CALL(mock, B).InSequence(s1);
    EXPECT_CALL(mock, C).InSequence(s2);
    Expectation exp_d = EXPECT_CALL(mock, D).InSequence(s2);
    EXPECT_CALL(mock, E).After(exp_b, exp_d);

    mock.A();
    mock.B();
    mock.C();
    mock.D();
    mock.E();
}

PS可以完全替代InSequence用After有一點點簡單的代碼。

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