我想創建一個將列印“|”的專案 字符為 4 層 1 3 5 7 類似
|
|||
|||||
|||||||
我為此寫了一個 for 回圈，代碼在這里：
for (int i = 1; i <= 4; i ) {
//for loop for displaying space
for (int s = i; s < 4; s ) {
cout << " ";
}
//for loop to display star equal to row number
for (int j = 1; j <= (2 * i - 1); j ) {
cout << "|";
}
// ending line after each row
cout << "\n";
}
那么我如何制作一個可以接受用戶輸入的代碼
cout << "Please enter a row number \n" << "Please enter a column number" << endl;
假設用戶輸入 2 作為行號 2 作為列號我希望輸出類似于
|
|
|||||
|||||||
洗掉 2 個“|” 來自第二行的字符首先我認為將每個字符放在一個陣列中，如 char arr[] = { '|' , '||' , '|||', '||||'} 并根據用戶輸入洗掉，但我失敗了。有什么幫助嗎？
uj5u.com熱心網友回復：
將一堆條形限制為 4 個級別，這應該有效：
- 您基本上只需要固定大小的條形字串“|”。
- 然后
n從該字串中洗掉連續字符。 - 您唯一需要計算的是開始洗掉的起始索引，然后
n用空格替換字符。 - 您可以添加一些檢查
row和col邊界。
[演示]
#include <iostream> // cout
#include <string>
int main()
{
std::string bars(16, '|');
auto get_start_deleting_pos = [](int row, int col) {
if (row == 1) { if (col > 1) { return -1; } return 0; }
else if (row == 2) { if (col > 3) { return -1; } return col; }
else if (row == 3) { if (col > 5) { return -1; } return 3 col; }
else if (row == 4) { if (col > 7) { return -1; } return 8 col; }
else return -1;
};
auto print_bars = [&bars]() {
std::cout << " " << bars[0] << "\n";
std::cout << " " << bars.substr(1, 3) << "\n";
std::cout << " " << bars.substr(4, 5) << "\n";
std::cout << bars.substr(9) << "\n";
};
auto start_deleting_from_row{4};
auto start_deleting_from_col{1};
auto num_chars_to_delete{4};
auto pos{ get_start_deleting_pos(start_deleting_from_row, start_deleting_from_col) };
if (pos != -1)
{
bars.replace(pos, num_chars_to_delete, num_chars_to_delete, ' ');
}
print_bars();
}
如果你想有一個更通用的解決方案，在用戶輸入level時，row并col開始從洗掉和要洗掉的字符數：
[演示]
#include <iostream> // cout
#include <string>
auto get_size_for_levels(int l) { return l*l; }
auto get_index_for_row_and_col(int row, int col) { return (row - 1) * (row - 1) - 1 col; }
auto get_num_cols_for_row (int row) { return row * 2 - 1; }
auto check_row_and_col(int levels, int row, int col) {
if (row < 1 or levels < row) { return false; }
if (col < 1 or get_num_cols_for_row(row) < col) { return false; }
return true;
}
int main()
{
auto levels{7}; // levels start at 1
auto start_deleting_from_row{4}; // rows start at 1
auto start_deleting_from_col{5}; // cols start at 1
auto num_chars_to_delete{6};
std::string bars(get_size_for_levels(levels), '|');
if (check_row_and_col(levels, start_deleting_from_row, start_deleting_from_col))
{
bars.replace(
get_index_for_row_and_col(start_deleting_from_row, start_deleting_from_col),
num_chars_to_delete,
num_chars_to_delete,
' ');
}
for (int l{1}; l <= levels; l)
{
std::cout
<< std::string(levels - l, ' ')
<< bars.substr(get_index_for_row_and_col(l, 1), get_num_cols_for_row(l))
<< "\n";
}
}
uj5u.com熱心網友回復：
這是一個解決方案：
#include <iostream>
#include <vector>
std::size_t getLayerCount( )
{
std::cout << "How many layers to print: ";
std::size_t layerCount { };
std::cin >> layerCount;
return layerCount;
}
std::vector< std::vector<char> > generateShape( const std::size_t layerCount )
{
const std::size_t MAX_CHAR_COUNT_IN_A_ROW { layerCount * 2 };
constexpr char spaceChar { ' ' };
std::vector< std::vector<char> > shape( layerCount, std::vector<char>( MAX_CHAR_COUNT_IN_A_ROW, spaceChar ) );
for ( std::size_t row { }; row < layerCount; row )
{
for ( std::size_t offset { layerCount - row - 1 }; offset < layerCount row; offset )
{
shape[ row ][ offset ] = '|';
}
shape[ row ][ MAX_CHAR_COUNT_IN_A_ROW - 1 ] = '\0';
}
return shape;
}
void printShape( const std::vector< std::vector<char> >& shape )
{
for ( const auto& row : shape )
{
std::cout.write( row.data( ), row.size( ) ).write( "\n", 1 );
}
}
void deleteSpecificChars( std::vector< std::vector<char> >& shape )
{
std::cout << "Please enter a row number: ";
std::size_t rowNumber { };
std::cin >> rowNumber;
std::cout << "Please enter a column number: ";
std::size_t colNumber { };
std::cin >> colNumber;
--rowNumber;
--colNumber;
const std::size_t layerCount { shape.size( ) };
const std::size_t posOfFirstCharInRow { layerCount - rowNumber - 1 };
const std::size_t posOfTargetCharInRow { posOfFirstCharInRow colNumber };
const std::size_t posOfLastCharInRow { posOfFirstCharInRow ( 2 * rowNumber ) };
for ( std::size_t idx { posOfTargetCharInRow }; idx <= posOfLastCharInRow; idx )
{
shape[ rowNumber ][ idx ] = ' ';
}
}
int main( )
{
const std::size_t layerCount { getLayerCount( ) };
std::vector< std::vector<char> > shape { generateShape( layerCount ) };
printShape( shape );
deleteSpecificChars( shape );
printShape( shape );
return 0;
}
示例輸入/輸出：
How many layers to print: 4
|
|||
|||||
|||||||
Please enter a row number: 2
Please enter a column number: 2
|
|
|||||
|||||||
另一個：
How many layers to print: 5
|
|||
|||||
|||||||
|||||||||
Please enter a row number: 4
Please enter a column number: 4
|
|||
|||||
|||
|||||||||
轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/400864.html
標籤：C 数组 视觉工作室-2015 特点 视觉工作室2019