我有從 mongodb 到陣列的資料,我想處理回傳資料以按日期和其他值拆分它,這是我到目前為止得到的,我需要一些幫助來處理結果
<?php
$stats=array(
array("source"=>501,"status"=>"answered","dest"=>"100","date"=>"2022-17-01"),
array("source"=>501,"status"=>"noAnswer","dest"=>"120","date"=>"2022-17-01"),
array("source"=>501,"status"=>"answered","dest"=>"100","date"=>"2022-18-01"),
array("source"=>502,"status"=>"answered","dest"=>"120","date"=>"2022-17-01"),
array("source"=>502,"status"=>"answered","dest"=>"130","date"=>"2022-17-01"),
array("source"=>502,"status"=>"answered","dest"=>"110","date"=>"2022-18-01")
);
$new1 = array();
$answer = 0;
$noanswer = 0;
$lastsrc = '';
$lastdate = '';
$dest=0;
foreach ($stats as $new) {
$src = $new['source'];
$date = $new['date'];
if ( $lastsrc == $src && $lastdate == $date ) {
$dest ;
if($new['status'] == 'answered'){ $answer ; }
if($new['status'] == 'noanswer'){ $noanswer ;}
$new1[] = array('source' => $src,
'date' => $date,
'ans' => $answer,
'nonans' => $noanswer,
'dest' => $dest );
} else if ( $lastsrc == $src && $lastdate != $date ) {
$dest ;
if($new['status'] == 'answered'){ $answer ;}
if($new['status'] == 'noanswer'){ $noanswer ;}
$new1[] = array('source' => $src,
'date' => $date,
'ans' => $answer,
'nonans' => $noanswer,
'dest' => $dest );
} else {
$dest ;
if($new['status'] == 'answered'){ $answer ; }
if($new['status'] == 'noanswer'){ $noanswer ;}
$new1[] = array('source' => $src,
'date' => $date,
'ans' => $answer,
'nonans' => $noanswer,
'dest' => $dest );
$lastsrc = $src;
$lastdate = $date;
}
}
print_r($new1);
?>
我試圖實作的是按日期和源拆分資料,所以如果在 foreach 回圈中我找到相同的源和相同的日期,那么我修改陣列而不是創建新陣列,如果相反則創建新陣列
我試圖得到的結果是:
array("source"=>501,"ans"=>"1","noans" => 0,"dest"=>1,"date"=>"2022-17-01"),
array("source"=>501,"ans"=>"1","noAnswer" => 1,"dest"=>2,"date"=>"2022-18-01"),
array("source"=>502,"ans"=>"2","noans" => 0,"dest"=>2,"date"=>"2022-17-01"),
array("source"=>502,"ans"=>"1","noans" => 0,"dest"=>1,"date"=>"2022-18-01")
我不確定它是否正確,任何幫助將不勝感激謝謝
uj5u.com熱心網友回復:
<?php
$stats = [
[ 'source' => 501, 'status' => 'answered', 'dest' => '100', 'date' => '2022-17-01' ],
[ 'source' => 501, 'status' => 'noAnswer', 'dest' => '120', 'date' => '2022-17-01' ],
[ 'source' => 501, 'status' => 'answered', 'dest' => '100', 'date' => '2022-18-01' ],
[ 'source' => 502, 'status' => 'answered', 'dest' => '120', 'date' => '2022-17-01' ],
[ 'source' => 502, 'status' => 'answered', 'dest' => '130', 'date' => '2022-17-01' ],
[ 'source' => 502, 'status' => 'answered', 'dest' => '110', 'date' => '2022-18-01' ]
];
$result = [];
foreach ($stats as $stat) {
$source = $stat['source'];
$date = $stat['date'];
$closure = static fn($item) => $item['source'] === $source && $item['date'] === $date;
$found = array_filter($result, $closure);
if (count($found) === 0) {
$list = array_filter($stats, $closure);
$list = array_map(static fn($item) => [ 'status' => $item['status'], 'dest' => $item['dest'] ], $list);
$result[] = [
'source' => $source,
'date' => $date,
'answered' => count(array_filter(array_column($list, 'status'), static fn($item) => $item === 'answered')),
'noAnswer' => count(array_filter(array_column($list, 'status'), static fn($item) => $item === 'noAnswer')),
'dest' => count(array_column($list, 'dest')),
];
}
}
print_r($result);
uj5u.com熱心網友回復:
我真的不確定你在這里尋找什么,f.ex dest 的內容,但我認為這正是你想要的(?)。只需從要排序的欄位創建一個復合鍵并使用關聯陣列。(陣列中的單個級別使排序/合并以及array_values()之后提取值()變得容易)
$result = [];
foreach($stats as $stat) {
$key = $stat['source'].'_'.$stat['date'];
if (!array_key_exists($key, $result)) {
$result[$key] = $stat ['answered' => 0, 'noAnswer' => 0];
}
$result[$key][$stat['status']] ;
}
print_r(array_values($result));
['source' => 501, 'status' => answered, 'dest' => 100, 'date' => 2022-17-01, 'answered' => 1, 'noAnswer' => 1],
['source' => 501, 'status' => answered, 'dest' => 100, 'date' => 2022-18-01, 'answered' => 1, 'noAnswer' => 0],
['source' => 502, 'status' => answered, 'dest' => 120, 'date' => 2022-17-01, 'answered' => 2, 'noAnswer' => 0],
['source' => 502, 'status' => answered, 'dest' => 110, 'date' => 2022-18-01, 'answered' => 1, 'noAnswer' => 0]
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