不能為了我的生活讓它在C 中對齊

一直試圖讓它對齊，每個訊息來源都告訴我使用 left 和 setw，但無論我如何格式化它，我似乎都無法讓它作業。有人有想法么？

#include <iostream>
#include <string>
#include <iomanip> using namespace std;

int main() {   string name[5] = {"able", "beehive", "cereal", "pub", "deck"};   string lastName[5] = {"massive", "josh", "open", "nab", "itch"};   float score[5] = {12, 213, 124, 123, 55};   char grade[5] = {'g', 'a', 's', 'p', 'e'};   int counter = 5;    for (int i = 0; i < counter; i  ){
    cout << left
    << name[i] << " " << setw(15) << left
    << lastName[i] << setw(15) << left
    << score[i] << setw(20)
    << grade[i];     cout << endl;    } }

這是輸出：

able massive        12             g                   
beehive josh           213            a                   
cereal open           124            s                   
pub nab            123            p                   
deck itch           55             e

uj5u.com熱心網友回復：

setw設定下一個輸出的寬度。它不會追溯更改先前輸出的格式。而不是... << someoutput << setw(width)你想要的... << setw(width) << someoutput：

#include <iostream>
#include <string>
#include <iomanip> 
using namespace std;

int main() {   
    string name[5] = {"able", "beehive", "cereal", "pub", "deck"};   
    string lastName[5] = {"massive", "josh", "open", "nab", "itch"};  
    float score[5] = {12, 213, 124, 123, 55};   
    char grade[5] = {'g', 'a', 's', 'p', 'e'};   
    int counter = 5;   
    for (int i = 0; i < counter; i  ){
        cout << left <<  " " << setw(15) << left << name[i] 
             <<  setw(15) << left << lastName[i] 
             <<  setw(20) << score[i]
             << grade[i];   
        cout << endl;    
   } 
}

直播：

 able           massive        12                  g
 beehive        josh           213                 a
 cereal         open           124                 s
 pub            nab            123                 p
 deck           itch           55                  e

uj5u.com熱心網友回復：

這是您的代碼，經過一些重構：

#include <iostream>
#include <iomanip>
#include <string>
#include <array>


int main( )
{
    // use std::array instead of antiquated raw arrays, it does
    // the same job but more conveniently

    // also use value initialization like `{ }` instead of this `= { }`

    std::array<std::string, 5> name { "able", "beehive", "cereal", "pub", "deck" };
    std::array<std::string,5> lastName { "massive", "josh", "open", "nab", "itch" };
    std::array<float, 5> score { 12, 213, 124, 123, 55 };
    std::array<char, 5> grade { 'g', 'a', 's', 'p', 'e' };
    
    constexpr std::size_t counter { name.size( ) }; // `counter` can be a
                                                    // constant expression so
                                                    // declare it constexpr

    for ( std::size_t idx { }; idx < counter;   idx ) // std::size_t for the
    {                                                 // loop counters
        std::cout << std::left << ' '
        << std::setw(15) << std::left << name[idx]
        << std::setw(15) << std::left << lastName[idx]
        << std::setw(20) << std::left << score[idx]
        << std::setw(1) << std::left << grade[idx];

        std::cout << '\n';
    } 
}

輸出：

 able           massive        12                  g
 beehive        josh           213                 a
 cereal         open           124                 s
 pub            nab            123                 p
 deck           itch           55                  e

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