如果javascript中的陣列中存在某個值，則從陣列中洗掉一個陣列-有解無憂

如果在我的資料中包含某個值，則嘗試洗掉整個陣列。

解決這個問題的最佳方法是什么？

data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']]


var del_value = 'J-001';

function remove_from_list(list) {
    for( var i = 0; i < list.length; i  ) { 
        for( var j =0; j < Object.keys(list[i]).length.length; j  ) {
            if(del_value == list[i][j]) {
                list.splice(list[i], 1);
            }
        }
    }
    return list;
}

實際輸出

data = 
[['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']]

期望的結果——洗掉所有具有值的陣列 'J-001'

data = 
[['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001']]

uj5u.com熱心網友回復：

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']];

const input = "J-001";


// Approach 
// Filter element (use filter) who has not given input (use not includes for this)
const result = data.filter(dat => !dat.includes(input));

console.log(result);

過濾器包括

uj5u.com熱心網友回復：

您可以使用array#filterandarray#includes來基于不包括J-001.

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'], ['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'], ['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'], ['false', 'visiting-tommorrow', 'DVM-Kon','J-001']],
      result = data.filter(arr => !arr.includes('J-001'));
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如果元素的位置固定為第三。然后您可以直接使用比較該索引處的值。

顯示代碼片段

const data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'], ['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'], ['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'], ['false', 'visiting-tommorrow', 'DVM-Kon','J-001']],
      result = data.filter(arr => arr[3] !== 'J-001');
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

uj5u.com熱心網友回復：

使用Array.filter()和的替代方法Array.find()。

data = [['true', 'visiting-today', 'DVM-Wiessman','J-001'],
['false', 'visiting-tommorrow', 'DVM-Stevens','K-001'],
['true', 'visiting-tommorrow', 'DVM-Stevens','Z-001'],
['false', 'visiting-tommorrow', 'DVM-Kon','J-001']];

function removeFromList(list, delValue) {
  return list.filter(arr => !arr.find(value => value === delValue));
}

console.log(removeFromList(data, 'J-001'));

轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/414920.html

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