如何使用條件將子查詢添加到主查詢?請求的結果應該類似于:
select
`tasks`.*,
`users`.`name` as `user_name`,
(select count(*) from tasks_favorites on tasks_favorites.task_id = tasks.id and tasks_favorites.user_id = 38) as `is_favorite`
from `tasks`
left join `users` on `users`.`id` = `tasks`.`user_id`
where
`tasks`.`id` = 149
我嘗試這個查詢,但我得到一個錯誤:
$task = DB::table('tasks')
->select(
'tasks.*',
'users.name as user_name',
)
->when(Auth::check(), function($query) {
return $query->addSelect(
DB::table('tasks_favorites')->where('tasks_favorites.task_id', 'tasks.id')->where('tasks_favorites.user_id', auth()->user()->id)->count()
) ;
})
->leftJoin('users', 'users.id', 'tasks.user_id')
->where('tasks.id', $task_id)
->get()
->first() ;
uj5u.com熱心網友回復:
您是否嘗試過 selectRaw 或 raw 方法?
像這樣的東西
$task = DB::table('tasks')
->select(
'tasks.*',
'users.name as user_name',
)
->when(Auth::check(), function($query) {
return $query->addSelect(
DB::raw('select count(id) from tasks_favorites where tasks_favorites.task_id=tasks.id AND tasks_favorites.user_id='.auth()->user()->id.' as mycount')
);
})
->leftJoin('users', 'users.id', 'tasks.user_id')
->where('tasks.id', $task_id)
->get()
->first() ;
轉載請註明出處,本文鏈接:https://www.uj5u.com/caozuo/421593.html
標籤:
