我正在撰寫一個從 IDLE 'import this' 匯入的程式。我想列印文本中的字母數（程式不應區分小寫和大寫）例如。"Hello world" --> [h= 1, e= 1, l= 3...]
這是我在尋找解決方案時發現的
from collections import Counter
test_str = '''
The Zen of Python, by Tim Peters
Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!
'''
res = Counter(test_str)
print ("The characters are:\n "
str(res))
不幸的是，這個計數區分小寫和大寫，有人有更好的主意嗎？
上面的代碼列印了這個：
字符是：
Counter({' ': 124, 'e': 90, 't': 76, 'i': 50, 'a': 50, 'o': 43, 's': 43, 'n': 40, 'l': 33, 'r': 32, 'h': 31, '\n': 22, 'b': 20, 'u': 20, 'p': 20, '.': 18, 'y': 17, 'm': 16, 'c': 16, 'd': 16, 'f': 11, 'g': 11, 'x': 6, '-': 6, 'v': 5, ',': 4, "'": 4, 'w': 4, 'T': 3, 'S': 3, 'A': 3, 'I': 3, 'P': 2, 'E': 2, 'k': 2, 'N': 2, '*': 2, 'Z': 1, 'B': 1, 'C': 1, 'F': 1, 'R': 1, 'U': 1, 'D': 1, '!': 1})
uj5u.com熱心網友回復：
test_str.lower(). 此外，您可以在不匯入 Counter 的情況下使用len()
轉載請註明出處，本文鏈接：https://www.uj5u.com/caozuo/442840.html
標籤：Python python-3.x
上一篇：將字符與串列單詞中的串列進行比較