當我使用 Spring Boot 應用程式和 JPA 在我的名為 schooldb 的資料庫中創建一個表時,代碼運行良好,但我無法自動創建一個表,并且必須使用 CMD 或任何其他終端顯式創建它IDE。
這是我的存盤庫類
package com.jpabasics.jpaBasics.enitity;
import lombok.AllArgsConstructor;
import lombok.Builder;
import lombok.Data;
import lombok.NoArgsConstructor;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity
@Data
@NoArgsConstructor
@AllArgsConstructor
@Builder
public class Student {
@Id
private long studentId;
private String firstName;
private String lastName;
private String emailId;
private String guardianName;
private String guardianEmail;
private String guardianMobile;
}
這是我的 POM.xml 檔案
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.6.4</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<groupId>com.jpabasics</groupId>
<artifactId>jpaBasics</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>jpaBasics</name>
<description>Jpa basics</description>
<properties>
<java.version>11</java.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.projectlombok</groupId>
<artifactId>lombok</artifactId>
<optional>true</optional>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<excludes>
<exclude>
<groupId>org.projectlombok</groupId>
<artifactId>lombok</artifactId>
</exclude>
</excludes>
</configuration>
</plugin>
</plugins>
</build>
</project>
這也是我的 application.properties 檔案
# Database Config : mysql
spring.datasource.url = jdbc:mysql://localhost:3306/schooldb
spring.datasource.username = root
spring.datasource.password = Lko@6388895330
spring.datasource.driver-class-name = com.mysql.cj.jdbc.Driver
# Hibernate Configuration
spring.jpa.generate-ddl=true
spring.jpa.hibernate.ddl.auto = update
spring.jpa.show-sql = true
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQL8Dialect
有人可以幫我解決這個問題嗎?
uj5u.com熱心網友回復:
您缺少在資料庫中構建表以托管物體所需的 @table 注釋。此外,對列進行注釋也是一種很好的習慣,以確保它們被正確命名(盡管在你的情況下,它們會被正確決議)。例如:
package com.jpabasics.jpaBasics.enitity;
import lombok.AllArgsConstructor;
import lombok.Builder;
import lombok.Data;
import lombok.NoArgsConstructor;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity
@Table(name="STUDENTS")
@Data
@NoArgsConstructor
@AllArgsConstructor
@Builder
public class Student {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "STUDENT_ID")
private long studentId;
@Column(name = "FIRST_NAME")
private String firstName;
@Column(name = "LAST_NAME")
private String lastName;
@Column(name = "EMAIL_ID")
private String emailId;
@Column(name = "GUARDIAN_NAME")
private String guardianName;
@Column(name = "GUARDIAN_EMAIL")
private String guardianEmail;
@Column(name = "GUARDIAN_MOBILE")
private String guardianMobile;
}
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