如何為我自己的代碼編輯器創建不同檔案夾的python檔案的函式？

我正在創建一個代碼編輯器，但我的代碼僅運行 python 檔案，該檔案位于代碼編輯器檔案也存在的同一檔案夾中，當我在側欄中打開另一個檔案夾并從中選擇一個檔案并運行它時，我的終端顯示錯誤我試過很多次，但我無法修復它 請告訴我如何修復它

錯誤：-

python: can't open file 'D:\\coding notes\\pytho project\\Anmol.py': [Errno 2] No such file or directory

這是我的代碼：-

import os
import subprocess
from tkinter import*
from tkinter import ttk
from tkinter.filedialog import askdirectory, asksaveasfilename
def process_directory(parent,path):
    for i in os.listdir(path):
        abspath = os.path.join(path,i)
        dirv = os.path.isdir(abspath)
        oid = tree.insert(parent,END,text=i,open=False)
        if dirv:
            process_directory(oid,abspath)
def Open(event=None):
    global path
    for i in tree.get_children():
        tree.delete(i)
    path = askdirectory()
    abspath = os.path.abspath(path)
    root_node = tree.insert("",END,text=abspath,open=True)
    process_directory(root_node,abspath)
def select_file(event=None):
    global file
    item = tree.selection()
    file = tree.item(item,"text")
    abspath = os.path.join(path,file)
    editor.delete(1.0,END)
    with open(abspath,"r") as f:
        editor.insert(1.0,f.read())
def save(event=None):
    global file
    if file == "":
        saveas()
    else:
        item = tree.selection()
        file = tree.item(item,"text")
        filepath = os.path.join(path,file)
        with open(file,"w") as f:
            f.write(editor.get(1.0,END))
        root.title(os.path.basename(file)   "-Python")
def saveas(event=None):
    global file
    file = asksaveasfilename(defaultextension=".py",filetypes=[("Python Files","*.py")])
    if file == "":
        file = None
    else:
        with open(file,"w") as f:
            f.write(editor.get(1.0,END))
        root.title(os.path.basename(file)   "-Python")
def run(event=None):
    global file
    if file == "":
        pass
    else:
        command = f"python {file}"
        run_file = subprocess.Popen(command,stdout=subprocess.PIPE,stderr=subprocess.PIPE,shell=True)
        Output, error = run_file.communicate()
        output.insert(END,f"{file}>>\n")
        output.insert(END,Output)
        output.insert(END,error)
root = Tk()
tree = ttk.Treeview()
tree.pack(side=LEFT,fill=BOTH)
file = ""
path = ""
editor = Text()
editor.pack(expand=True,fill=BOTH)
output = Text(height=15)
output.pack(expand=True,fill=BOTH)

root.bind("<Control-Alt-o>",Open)
root.bind("<Control-s>",save)
root.bind("<Control-Alt-s>",saveas)
root.bind("<Shift-Return>",run)
tree.bind("<<TreeviewSelect>>",select_file)





root.mainloop()

uj5u.com熱心網友回復：

如果選中的檔案在選中檔案夾的子檔案夾內，那么inside創建的絕對路徑不是正確的絕對路徑（錯過子檔案夾資訊）。abspath = os.path.join(path,file)select_file()

values一種方法是在插入樹視圖時將絕對路徑保存在選項中：

def process_directory(parent,path):
    for i in os.listdir(path):
        abspath = os.path.join(path,i)
        dirv = os.path.isdir(abspath)
        # save the absolute path in "values" option
        oid = tree.insert(parent,END,text=i,open=False,values=(abspath,))
        if dirv:
            process_directory(oid,abspath)

然后在里面select_file()你可以通過獲取values選項而不是加入選定的檔案夾和選定的檔案來獲取絕對路徑：

def select_file(event=None):
    global file
    item = tree.selection()
    # get the absolute path
    file = tree.item(item,"values")[0]
    if os.path.isfile(file):
        editor.delete(1.0,END)
        with open(file,"r") as f:
            editor.insert(1.0,f.read())

同樣適用于save()。

標籤：Python tkinter

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