example of getDepart date format
getDepart = 2022-04-29
desired result 29 APR, 2022
const getStringDepart = () => {
const months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT",
"NOV", "DEC"];
const departArray = getDepart.split("-");
const departDay = departArray[2];
const departYear = departArray[0];
const departMonth = ????????????
const departString = `${departDay} ${departMonth}, ${departYear}`;
return departString;
}
我正在嘗試將我的 YYYY-MM-DD 字串日期格式轉換為DD mon, YYYY字串。我正在考慮使用帶有月份的陣列并將月份編號與其索引匹配,但我找不到這樣做的方法。
uj5u.com熱心網友回復:
你只需要傳遞month - 1你的陣列。它應該正確回傳月份。
getDepart = '2022-04-29';
const getStringDepart = () => {
const months = ["JAN", "FEB", "MAR", "APR", "MAY", "JUN", "JUL", "AUG", "SEP", "OCT", "NOV", "DEC"];
const departArray = getDepart.split("-");
const departDay = departArray[2];
const departYear = departArray[0];
const departMonth = departArray[1];
const departString = `${departDay} ${months[Number(departMonth) - 1]}, ${departYear}`;
return departString;
}
function test() {
console.log(getStringDepart())
}
輸出:

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標籤:javascript 数组
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