未能捕獲以下命令的回應；
URL="https://gsdfdsfithub.com/gitexpert/testGithub.git" > /dev/null
git ls-remote $URL -q
if [ $? -nq 0 ]; then
echo "Failed, please provide valid url"
fi
輸出：
fatal: unable to access 'https://gsdfdsfithub.com/gitexpert/testGithub.git/': Received HTTP code 404 from proxy after CONNECT
128
line 4: [: -nq: binary operator expected
我嘗試了上面的代碼片段，但它仍然捕捉到錯誤。我想抑制錯誤訊息，并將自定義訊息作為輸出。像下面
"Failed, please provide valid url"
uj5u.com熱心網友回復：
將標準輸出和標準錯誤列印到/dev/null.
URL="https://gsdfdsfithub.com/gitexpert/testGithub.git" > /dev/null
git ls-remote $URL -q >> /dev/null 2>&1
if [ $? != 0 ]; then
echo "Failed, please provide valid url"
fi
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