我需要創建一個函式來搜索某個字串是否在一個陣列中，并創建一個包含它的所有元素（串列）的串列。例如：
word = 'busy'
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]
所以我的輸出應該是：
[['99', 'Normal', [], ['busy', '0'], 362.01, 'working', '1']]
但我只得到表明字串不存在的驗證，而它顯然存在。這是代碼：
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]
def searchBusyWorkers(array):
busy = []
for x in array:
if 'busy' in x:
ind = x.index('busy')
busy.append(array[ind])
return busy
else:
return "No workers have that condition."
uj5u.com熱心網友回復：
'busy' in x失敗是因為“忙”嵌套更深一層。換句話說，'busy' in xx 中沒有但有一個包含字串“busy”的子陣列。
由于您提到“忙碌”將始終位于特定索引處，因此您需要解包以獲取子陣列，然后檢查該索引 -
for x in array:
elements, *_ = x
if 'busy' in elements[3]:
print(x)
輸出
[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']]
uj5u.com熱心網友回復：
試試這個
word = 'busy'
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],
[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]
def searchBusyWorkers(array,word):
out = []
for a in array:
for i in a:
for x in i:
try:
if word in x:
out.append(i)
except TypeError:
if word == x:
out.append(i)
if out:
return out
return "No workers have that condition."
print(searchBusyWorkers(array,word))
輸出
[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']]
uj5u.com熱心網友回復：
我會這樣做：
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]
def searchforword(word, array):
return([y for x in array for y in x for i in y if word in str(i)])
結果：
word = 'busy'
print(searchforword(word, array))
[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']]
word = 'free'
print(searchforword(word, array))
[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]
uj5u.com熱心網友回復：
這應該作業
new_list = []
for i in range(len(array)):
for j in (array[i]):
if isinstance(j, list):
try:
for r in j:
if word in r:
new_list.append(array[i])
except:
...
if word in j or word in array[i]: #update
new_list.append(array[i])
print(*new_list) # Update
輸出：
[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']]
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