如何從包含陣列陣列的JSON中獲取資料到顫動的物件中

我得到的 json 看起來像這樣：

{"-N42h_BKjWaEZRJyH8vS":[{"Data":"06/2022","imie":"John","DayList":[["7.50","12.00"],["00.00","00.00"],["8.00","16.00"],["00.00","00.00"],["00.00","00.00"],["7.50","15.00"],["00.00","00.00"],["00.00","00.00"],["00.00","00.00"],["8.00","15.25"],["00.00","00.00"],["00.00","00.00"],["7.50","15.00"],["00.00","00.00"]],"surname":"Smith"}]}

“DayList”中的每個串列代表單獨的作業日。例如 ["7.50","12.00"] 只是說，作業時間從 7.30 開始，到 12 結束。每天索引也代表一個月中的一天 例如索引 0 是 01/06/2022，索引 1 是 02/06/ 2022 年等等。整個串列附加到一個人，在本例中為 John Smith。

我的 Day 模型如下所示：

class Day {
  String name;
  DateTime dateTime;
  double startTime;
  double endTime;

  Day({
    required this.name,
    required this.dateTime,
    required this.startTime,
    required this.endTime,
  });
}

任何人都知道如何基于這個 json 創建物件串列？也許有更好的方法來創建這樣的 json？

uj5u.com熱心網友回復：

class DayDatum {
DayDatum({
    this.data,
    this.imie,
    this.dayList,
    this.surname,
});

String data;
String imie;
List<List<String>> dayList;
String surname;

factory DayDatum.fromJson(Map<String, dynamic> json) => DayDatum(
    data: json["Data"],
    imie: json["imie"],
    dayList: List<List<String>>.from(json["DayList"].map((x) => List<String>.from(x.map((x) => x)))),
    surname: json["surname"],
);

Map<String, dynamic> toJson() => {
    "Data": data,
    "imie": imie,
    "DayList": List<dynamic>.from(dayList.map((x) => List<dynamic>.from(x.map((x) => x)))),
    "surname": surname,
};
}

您可以使用此模型來決議每個物件的資料

uj5u.com熱心網友回復：

請檢查以下鏈接以獲取 json 決議器。 https://docs.flutter.dev/development/data-and-backend/json#setting-up-json_serializable-in-a-project

如果您有任何疑問，請告訴我。

uj5u.com熱心網友回復：

import 'dart:convert';

Data dataFromJson(String str) => Data.fromJson(json.decode(str));

String dataToJson(Data data) => json.encode(data.toJson());

class Data {
  Data({
    this.listOfDays,
  });

  List<personalInfo>? listOfDays;

  factory Data.fromJson(Map<String, dynamic> json) => Data(
        listOfDays: List<personalInfo>.from(json["-N42h_BKjWaEZRJyH8vS"]
            .map((x) => personalInfo.fromJson(x))),
      );

  Map<String, dynamic> toJson() => {
        "-N42h_BKjWaEZRJyH8vS":
            List<dynamic>.from(listOfDays!.map((x) => x.toJson())),
      };
}

class personalInfo {
  personalInfo({
    this.data,
    this.imie,
    this.dayList,
    this.surname,
  });

  String? data;
  String? imie;
  List<List<String>>? dayList;
  String? surname;

  factory personalInfo.fromJson(Map<String, dynamic> json) =>
      personalInfo(
        data: json["Data"],
        imie: json["imie"],
        dayList: List<List<String>>.from(
            json["DayList"].map((x) => List<String>.from(x.map((x) => x)))),
        surname: json["surname"],
      );

  Map<String, dynamic> toJson() => {
        "Data": data,
        "imie": imie,
        "DayList": List<dynamic>.from(
            dayList!.map((x) => List<dynamic>.from(x.map((x) => x)))),
        "surname": surname,
      };
}

您也可以使用此站點直接創建模型

標籤：json 扑 镖 后端

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