public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain) throws ServletException, IOException {
chain.doFilter(req, resp);
System.out.println("f2");
chain.doFilter(req,resp);
}
<filter>
<filter-name>Filter2</filter-name>
<filter-class>com.test.Filter2</filter-class>
</filter>
<filter-mapping>
<filter-name>Filter2</filter-name>
<url-pattern>/s1</url-pattern>
</filter-mapping>
@WebServlet(name = "Servlet1", urlPatterns = "/s1")
public class Servlet1 extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.getWriter().println("suc");
}
<form action="s1" method="post">
<div>
<input type="submit" value="https://bbs.csdn.net/topics/確認">
</div>
請教下各位大佬，控制臺輸出4個f2，頁面列印兩個suc，是因為啥？按照我的理解，點擊按鈕，跳轉/s1，對/s1資源請求過濾，輸出一次f2，一次suc，不知道哪里出了問題？
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標籤：Java EE
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