#include<stdio.h>
#define H_WAGE1 8.75
#define H_WAGE2 9.33
#define H_WAGE3 10.00
#define H_WAGE4 11.20
#define TIME1 30
#define TIME2 40
#define RATE_T 1.5
#define RATE1 0.15
#define RATE2 0.2
#define RATE3 0.25
#define BREAK1 300
#define BREAK2 450
int main(void)
{
float time,total,tax,net,H_WAGE;
int choice;
printf("*****************************************************************\n");
printf("Enter the number corresponding to the desired pay rate or action:\n") ;
printf("(1)$8.75/hr (2)$9.33/hr\n");
printf("(3)$10.00/hr (4)$11.20/hr\n");
printf("(5)quit\n");
printf("*****************************************************************\n");
printf("Enter the choice:\n");
scanf("%d",&choice);
if(choice==1||choice==2||choice==3||choice==4||choice==5)
{
switch(choice)
{
case 1:
H_WAGE=H_WAGE1;
printf("Your choice is 1,$8.75/hr.\n");
break;
case 2:
H_WAGE=H_WAGE2;
printf("Your choice is 2,$9.33/hr.\n");
break;
case 3:
H_WAGE=H_WAGE3;
printf("Your choice is 3,$10.00/hr.\n");
break;
case 4:
printf("Your choice is 4,$11.20/hr.\n");
H_WAGE=H_WAGE4;
break;
case 5:
printf("Your choice is 5,to quit.\n");
H_WAGE=0;
break;
default:
printf("Enter the right number.\n");
break;
}
}
else
printf("Enter the right number.\n");
while(H_WAGE!=0)
{
printf("Please enter the working time per week:\n");
while(scanf("%f",&time)==1)
{
if(time>=0)
{
if(time<=TIME1)
{
total=time*H_WAGE;
tax=total*RATE1;
}
else if(time<TIME2)
{
total=time*H_WAGE;
tax=TIME1*H_WAGE*RATE1+(time-TIME1)*H_WAGE*RATE2;
}
else
{
time=TIME2+(time-TIME2)*RATE_T;
total=time*H_WAGE;
if(total<BREAK2)
tax=TIME1*H_WAGE*RATE1+(time-TIME1)*H_WAGE*RATE2;
else
tax=TIME1*H_WAGE*RATE1+(BREAK2-BREAK1)*RATE2+(total-BREAK2)*RATE3;
}
net=total-tax;
printf("Time is %.2f hours,total income is %.2f,tax is %.2f,net income is %.2f\n"
,time,total,tax,net);
}
else
printf("Time cannot be negtive.\n") ;
printf("Enter time again or q to quit.\n");
H_WAGE=0;
}
}
printf("Done!\n");
return 0;
}
uj5u.com熱心網友回復：
第一個if...else陳述句完全是多余的，switch陳述句就行了。uj5u.com熱心網友回復：
初學者要學的第一件事是代碼縮進寫好
處理好這件事之前 不用討論怎么評價代碼
不入流
uj5u.com熱心網友回復：
多謝指教 ，以后多注意uj5u.com熱心網友回復：
多謝指教，我再修改一下轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/163679.html
標籤：C語言