小小明:
一名從初中開始編程,已具備10年以上基礎編碼經驗的碼農,
之前跟一些小伙伴有個討論:

大概就是很多跟資料打交道的朋友都面對過很復雜的excel公式,有時嵌套層數特別多,肉眼觀看很容易蒙圈,
有了這樣的需求,我就有了解決問題的想法,說干就干,于是一個比較牛逼的excel公式格式化的工具就出現了,
效果體驗
先看看效果吧:
=IF(C11>100%*C4,IF(C11<=200%*C4,C11*50%-C4*15%,C11*60%-C4*35%),IF(C11<=C4*50%,C11*30%,C11*40%-C4*5%))
的格式化結果是:
=IF(
C11>100%*C4,
IF(
C11<=200%*C4,
C11*50%-C4*15%,
C11*60%-C4*35%
),
IF(
C11<=C4*50%,
C11*30%,
C11*40%-C4*5%
)
)

(SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)/SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100-MIN(SMA(MAX(CLOSE-DELAY(
CLOSE,1),0),12,1)/SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100,12))/(MAX(SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,
1)/SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100,12)-MIN(SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)/SMA(ABS(
CLOSE-DELAY(CLOSE,1)),12,1)*100,12))
的格式化結果為:
(
SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)
/
SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)
*
100-MIN(
SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)
/
SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100,
12
)
)
/
(
MAX(
SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)
/
SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100,
12
)
-
MIN(
SMA(MAX(CLOSE-DELAY(CLOSE,1),0),12,1)
/
SMA(ABS(CLOSE-DELAY(CLOSE,1)),12,1)*100,
12
)
)
[外鏈圖片轉存失敗,源站可能有防盜鏈機制,建議將圖片保存下來直接上傳(img-yWj19ysf-1608598379417)(https://gitee.com/wangzhouming/blogimgs/raw/master/img/image-20201214165643898.png)]
=IF(ROW()>COLUMN(),"",IF(ROW()=COLUMN(),$B15,ROUNDDOWN($B15*INDIRECT(SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(),
4),1,"")&56),0)))
的格式化結果為:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(
SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(), 4),1,"")
&
56
),
0
)
)
)

(文末有體驗網址)
不過接下來,將公布這套格式化程式的完整代碼和開發思想,有技術能力的小伙伴可以考慮改進該代碼,
完整代碼
__author__ = 'xiaoxiaoming'
from collections import deque
import re
class Node:
def __init__(self, parent=None, tab_size=0):
self.parent = parent
self.tab_size = tab_size
self.data = []
def is_single_node(self):
for e in self.data:
if not isinstance(e, str):
return False
return True
def get_single_text(self):
return "".join(self.data)
def split_text_blocks(excel_func_text):
"""
將excel公式字串,按照一定的規則切割成陣列
:param excel_func_text: 被切割的excel公式字串
:return: 切割后的結果
"""
excel_func_text = excel_func_text.replace('\n', '').replace('\r', '')
excel_func_text = re.sub(" +", " ", excel_func_text)
lines = []
i, j = 0, 0
while j < len(excel_func_text):
c = excel_func_text[j]
if (c == '(' and excel_func_text[j + 1] != ')') or c == ',':
lines.append(excel_func_text[i:j + 1])
i = j = j + 1
elif c == ')' and excel_func_text[j - 1] != '(':
if i < j:
lines.append(excel_func_text[i:j])
i = j # 起始檔案塊置于)處
# 以下代碼查找,如果中間不包含(或),則將)和,之間的文本塊加入到劃分結果
k = excel_func_text.find(",", j + 1)
l = excel_func_text.find("(", j + 1, k)
m = excel_func_text.find(")", j + 1, k)
if k != -1 and l == -1 and m == -1:
lines.append(excel_func_text[i:k + 1])
i = j = k + 1
elif j + 1 < len(excel_func_text) and excel_func_text[j + 1] != ')':
lines.append(")")
lines.append(excel_func_text[j + 1])
i = j = j + 2
else:
lines.append(")")
i = j = j + 1
elif c == '"':
j = excel_func_text.find('"', j + 1) + 1
else:
j += 1
return lines
blank_char_count = 2
def combine_node(root, text_max_length=60, max_combine_layer=3):
"""
合并最內層的只有純文本子節點的節點為單個文本節點
:param root: 被合并的節點
:param text_max_length: 合并后的文本長度不超過該引數,則應用該合并替換原節點
:param max_combine_layer: 最大合并層數
:return:
"""
for _ in range(max_combine_layer):
no_change = True
stack = deque([root])
while stack:
node = stack.pop()
tmp = {}
for i, e in enumerate(node.data):
if isinstance(e, Node):
if e.is_single_node():
single_text = e.get_single_text()
if len(single_text) < text_max_length:
tmp[i] = single_text
else:
stack.append(e)
for i, e in tmp.items():
node.data[i] = e
if len(tmp) != 0:
no_change = False
if no_change:
break
def node_next_line(node):
for i, e in enumerate(node.data):
if isinstance(e, str):
if i == 0 or i == len(node.data) - 1:
tab = node.tab_size - 1
else:
tab = node.tab_size
yield f"{' ' * blank_char_count * tab}{e}"
else:
yield from node_next_line(e)
def excel_func_format(excel_func_text, blank_count=2, combine_single_node=True, text_max_length=60,
max_combine_layer=3):
"""
將excel公式格式化成比較容易閱讀的格式
:param excel_func_text: 被格式化的excel公式字串
:param blank_count: 最終顯示的格式化字串的1個tab用幾個空格表示
:param combine_single_node: 是否合并純文本節點,該引數設定為True后面的引數才生效
:param text_max_length: 合并后的文本長度不超過該引數,則應用該合并替換原節點
:param max_combine_layer: 最大合并層數
:return: 格式化后的字串
"""
global blank_char_count
blank_char_count = blank_count
blocks = split_text_blocks(excel_func_text)
# print("\n".join(blocks))
# print('-----------拆分結果-----------')
tab_size = 0
node = root = Node()
for block in blocks:
if block.endswith("("):
tab_size += 1
child_node = Node(node, tab_size)
node.data.append(child_node)
node = child_node
node.data.append(block)
elif block.startswith(")"):
tab_size -= 1
node.data.append(block)
node = node.parent
else:
node.data.append(block)
if combine_single_node:
combine_node(root, text_max_length, max_combine_layer)
result = [line for line in node_next_line(root)]
return "\n".join(result)
處理流程淺析
下面都以如下公式作為示例:
=IF(ROW()>COLUMN(),"",IF(ROW()=COLUMN(),$B15,ROUNDDOWN($B15*INDIRECT(SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(),
4),1,"")&56),0)))
文本分塊切分
def split_text_blocks(excel_func_text):
"""
將excel公式字串,按照一定的規則切割成陣列
:param excel_func_text: 被切割的excel公式字串
:return: 切割后的結果
"""
excel_func_text = excel_func_text.replace('\n', '').replace('\r', '')
excel_func_text = re.sub(" +", " ", excel_func_text)
lines = []
i, j = 0, 0
while j < len(excel_func_text):
c = excel_func_text[j]
if (c == '(' and excel_func_text[j + 1] != ')') or c == ',':
lines.append(excel_func_text[i:j + 1])
i = j = j + 1
elif c == ')' and excel_func_text[j - 1] != '(':
if i < j:
lines.append(excel_func_text[i:j])
i = j # 起始檔案塊置于)處
# 以下代碼查找,如果中間不包含(或),則將)和,之間的文本塊加入到劃分結果
k = excel_func_text.find(",", j + 1)
l = excel_func_text.find("(", j + 1, k)
m = excel_func_text.find(")", j + 1, k)
if k != -1 and l == -1 and m == -1:
lines.append(excel_func_text[i:k + 1])
i = j = k + 1
elif j + 1 < len(excel_func_text) and excel_func_text[j + 1] != ')':
lines.append(")")
lines.append(excel_func_text[j + 1])
i = j = j + 2
else:
lines.append(")")
i = j = j + 1
elif c == '"':
j = excel_func_text.find('"', j + 1) + 1
else:
j += 1
return lines
s = """=IF(ROW()>COLUMN(),"",IF(ROW()=COLUMN(),$B15,ROUNDDOWN($B15*INDIRECT(SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(),
4),1,"")&56),0))) """
blocks = split_text_blocks(s)
for block in blocks:
print(block)
的運行結果為:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(
SUBSTITUTE(
ADDRESS(
1,
3+COLUMN()-ROW(),
4
),
1,
""
)
&
56
),
0
)
)
)
這端代碼首先替換掉所有的換行符,將多個空格替換為單個空格,然后將左右括號和逗號作為切分點進行切分,
但存在一些特殊情況,例如ROW()和COLUMN()括號內部沒有任何內容,所有這種括號應該作為普通字符處理,另外被""包含的字串可能包含括號,也應該作為普通字符,
構建多叉樹層次結構
設計資料結構:
class Node:
def __init__(self, parent=None, tab_size=0):
self.parent = parent
self.tab_size = tab_size
self.data = []
parent存盤父節點的指標,tab_size存盤當前節點的層級,data存盤當前節點的所有資料,
構建代碼:
tab_size = 0
node = root = Node()
for block in blocks:
if block.endswith("("):
tab_size += 1
child_node = Node(node, tab_size)
node.data.append(child_node)
node = child_node
node.data.append(block)
elif block.startswith(")"):
tab_size -= 1
node.data.append(block)
node = node.parent
else:
node.data.append(block)
構建完畢后,這段資料在記憶體中的結構(僅展示data)如下:

遍歷列印這顆多叉樹
def node_next_line(node):
for i, e in enumerate(node.data):
if isinstance(e, str):
if i == 0 or i == len(node.data) - 1:
tab = node.tab_size - 1
else:
tab = node.tab_size
yield f"{' ' * 2 * tab}{e}"
else:
yield from node_next_line(e)
result = [line for line in node_next_line(root)]
print("\n".join(result))
結果:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(
SUBSTITUTE(
ADDRESS(
1,
3+COLUMN()-ROW(),
4
),
1,
""
)
&
56
),
0
)
)
)
合并最內層的節點
顯然將最內層的node5節點合并一下閱讀性更好:

首先給資料結構增加判斷是否為純文本節點的方法:
class Node:
def __init__(self, parent=None, tab_size=0):
self.parent = parent
self.tab_size = tab_size
self.data = []
def is_single_node(self):
for e in self.data:
if not isinstance(e, str):
return False
return True
def get_single_text(self):
return "".join(self.data)
下面是合并純文本節點的實作,max_combine_layer決定了合并的最大次數,如果合并后長度超過text_max_length引數,則不應用這次合并:
from collections import deque
def combine_node(root, text_max_length=60, max_combine_layer=3):
"""
合并最內層的只有純文本子節點的節點為單個文本節點
:param root: 被合并的節點
:param text_max_length: 合并后的文本長度不超過該引數,則應用該合并替換原節點
:param max_combine_layer: 最大合并層數
:return:
"""
for _ in range(max_combine_layer):
no_change = True
stack = deque([root])
while stack:
node = stack.pop()
tmp = {}
for i, e in enumerate(node.data):
if isinstance(e, Node):
if e.is_single_node():
single_text = e.get_single_text()
if len(single_text) < text_max_length:
tmp[i] = single_text
else:
stack.append(e)
for i, e in tmp.items():
node.data[i] = e
if len(tmp) != 0:
no_change = False
if no_change:
break
合并一次:
combine_node(root, 100, 1)
result = [line for line in node_next_line(root)]
print("\n".join(result))
結果:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(
SUBSTITUTE(
ADDRESS(1,3+COLUMN()-ROW(), 4),
1,
""
)
&
56
),
0
)
)
)
合并二次:
combine_node(root, 100, 2)
result = [line for line in node_next_line(root)]
print("\n".join(result))
結果:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(
SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(), 4),1,"")
&
56
),
0
)
)
)
合并三次:
combine_node(root, 100, 3)
result = [line for line in node_next_line(root)]
print("\n".join(result))
結果:
=IF(
ROW()>COLUMN(),
"",
IF(
ROW()=COLUMN(),
$B15,
ROUNDDOWN(
$B15*INDIRECT(SUBSTITUTE(ADDRESS(1,3+COLUMN()-ROW(), 4),1,"")&56),
0
)
)
)
合并三次后的記憶體情況:

體驗網址
http://xiaoxiaoming.xyz:8088/excel
不保證永久有效,
轉載請註明出處,本文鏈接:https://www.uj5u.com/houduan/239052.html
標籤:python
上一篇:python基本資料型別

