#include < stdio.h >
char fun(char ch)
{
if (ch >= '0' && ch<='9')
//return '9' - (ch-'0'); 為什么改成下面那個會出亂碼
return '9' - ch;
return ch;
}
int main()
{
char c1, c2;
printf("\nThe result :\n");
c1 = '2';
c2 = fun(c1);
printf("c1=%c c2=%c\n", c1, c2);
c1 = '8'; c2 = fun(c1);
printf("c1=%c c2=%c\n", c1, c2);
c1 = 'a'; c2 = fun(c1);
printf("c1=%c c2=%c\n", c1, c2);
}
[code=c][code=c][/code][/code]
uj5u.com熱心網友回復：
//return '9' - (ch-'0'); 為什么改成下面那個會出亂碼return '9' - ch;
//////////////////
(ch-'0')轉換成了數值
return '9' - (ch-'0'); 為'9'- 數值，結果為字符‘0’到‘9’
return '9' - ch; 為'9' - 字符，結果為數值 0-9
uj5u.com熱心網友回復：
因為'9'-'1'和'9'-1是不一樣的。第一個得8，第二個得'8'，這樣輸出的'8'還是8，輸出的8是啥呢，可以查一下ASCII表轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/269204.html
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