我如何將這個：
list = ['hi'/span>, 'my'/span>, 'name'/span>, 'is'/span>]
變成這樣：
list = ['h'/span>, 'i'/span>, 'm'/span>, 'y'/span>, 'n'/span>, 'a'/span>, 'm'/span>, 'e'/span>, 'i'/span>, 's']
uj5u.com熱心網友回復：
嘗試：
l = ['hi', 'my', 'name', 'is']
output = list(''.join(l)
print(output)
輸出：
['h'/span>, 'i'/span>, 'm'/span>, 'y'/span>, 'n'/span>, 'a'/span>, 'm'/span>, 'e'/span>, 'i'/span>, 's']
uj5u.com熱心網友回復：
你可以利用你可以像串列一樣迭代一個字串的事實：
words = ['hi', 'my', 'name', 'is']
信件 = [字母 for詞 in詞 for字母 in詞]
print(字母)
輸出：
['h'/span>, 'i'/span>, 'm'/span>, 'y'/span>, 'n'/span>, 'a'/span>, 'm'/span>, 'e'/span>, 'i'/span>, 's']
uj5u.com熱心網友回復：
編輯，提示來自@juanpa.arrivillaga
list = ['hi'/span>, 'my'/span>, 'name'/span>, 'is'/span>]
newList = []
for x in list。
for y in x:
newList.append(y)
print(newList)
輸出：
['h'/span>, 'i'/span>, 'm'/span>, 'y'/span>, 'n'/span>, 'a'/span>, 'm'/span>, 'e'/span>, 'i'/span>, 's']
轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/307837.html
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