我想將時間從 12 小時格式轉換為 24 小時格式
這是我的代碼：
def change_time(time):
import datetime as dt
FMT12 = '%H:%M:%S %p'
FMT24 = '%H:%M:%S'
# time is a string
if time.find('PM') != -1: # if exists
t1 = dt.datetime.strptime(time, FMT12)
t2 = dt.datetime.strptime('12:00:00', FMT24)
time_zero = dt.datetime.strptime('00:00:00', FMT24)
return (t1 - time_zero t2).time()
else:
return dt.datetime.strptime(time, FMT12).time()
這是輸出：
print(change_time('09:52:08 PM')) # -> 21:52:08
所以，這段代碼正在運行，但我想要一個更好的版本。
uj5u.com熱心網友回復：
這是一種更快的作業方法：
from datetime import datetime
def change_time(time):
in_time = datetime.strptime(time, "%I:%M:%S %p")
new_time = datetime.strftime(in_time, "%H:%M:%S")
print(new_time)
change_time('09:52:08 PM')
輸出：
>>> 21:52:08
uj5u.com熱心網友回復：
def t12_to_24(time):
am_or_pm = time[-2] time[-1]
time_update = ''
if am_or_pm == 'am' or am_or_pm == 'AM':
for i in time[0:-3]:
time_update = i
elif am_or_pm == 'pm' or am_or_pm == 'PM':
change = ''
for i in time[0:2]:
change = i
c = 12 int(change)
if c >= 24:
c = 24 - c
c = list(str(c))
for i1 in c:
time_update = i1
for i2 in time[2:-3]:
time_update = i2
print(time_update)
time = list(input())
t12_to_24(time)
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