我需要過濾一組物件
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
我只需要陣列中的名稱（沒有鍵）
預期輸出
["fruit", "water"]
uj5u.com熱心網友回復：
你可以簡單地做
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" }
];
const arrayTwo = [33, 193];
let keepResult = [];
arrayOne.map((a1) => {
arrayTwo.map((a2) => {
if (a1.id === a2) {
keepResult.push(a1.name);
}
});
});
console.log("result show", keepResult);uj5u.com熱心網友回復：
1）您可以使用Map
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" },
];
const map = new Map();
arrayOne.forEach((o) => map.set(o.id, o.name));
const arrayTwo = [33, 193];
const result = arrayTwo.map((o) => map.get(o));
console.log(result);2）您還可以使用map和實作結果find
const arrayOne = [
{ id: 33, name: "fruit" },
{ id: 157, name: "car" },
{ id: 193, name: "water" },
];
const arrayTwo = [33, 193];
const result = arrayTwo.map((id) => arrayOne.find((o) => o.id === id)?.name);
console.log(result);uj5u.com熱心網友回復：
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
let newArray = arrayOne.filter(item => arrayTwo.includes(item.id)).map(item => item.name)
console.log(newArray);嘗試這個
uj5u.com熱心網友回復：
您也可以使用過濾器然后映射
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
var result = arrayOne.filter((itm) => arrayTwo.includes(itm.id)).map(prop => prop.name);
console.log(result);uj5u.com熱心網友回復：
此功能是您的解決方案：
const findNames = () => {
let names = []
arrayOne.forEach(item => {
if (arrayTwo.includes(item.id)) {
names = [...names, item.name]
}
})
return names
}
uj5u.com熱心網友回復：
這是您的compare()函式，用于根據兩個陣列獲取名稱陣列
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 157];
function compare(arrayOne, arrayTwo) {
let result = [];
arrayOne.filter(element => arrayTwo.indexOf(element.id) !== -1 ).forEach(element => { result.push(element.name) });
return result ;
}
uj5u.com熱心網友回復：
在第一個陣列上使用 flatmap 并僅包含那些具有id陣列 2 中包含的屬性的成員。
arrayOne.flatMap(({ id, name }) => arrayTwo.includes(id) ? [name]: []);
const arrayOne = [
{id: 33, name: "fruit"},
{id: 157, name: "car"},
{id: 193, name: "water"},
];
const arrayTwo = [33, 193];
const result = arrayOne.flatMap(({ id, name }) => arrayTwo.includes(id) ? [name]: []);
console.log(result);轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/360905.html
標籤：javascript 数组