對于下面嵌入的字典串列，如何根據key1路徑的字串長度對其進行排序？
jobs = [ {"key1":"path/123", "key2":list1}, \
{"key1":"path/12", "key2":list2}, \
{"key1":"path/1", "key2":list3} ]
預期輸出
sorted_jobs = [ {"key1":"path/1", "key2":list3} \
{"key1":"path/12", "key2":list2}, \
{"key1":"path/123", "key2":list1} ]
uj5u.com熱心網友回復：
只需定義key函式sorted：
sorted_jobs = sorted(jobs, key=lambda d: len(d['key1']))
uj5u.com熱心網友回復：
使用key引數sorted：
res = sorted(jobs, key=lambda x: len(x["key1"]))
print(res)
輸出
[{'key1': 'path/1', 'key2': []}, {'key1': 'path/12', 'key2': []}, {'key1': 'path/123', 'key2': []}]
作為替代，您可以使用普通的Python 函式，如下所示：
def key(d):
return len(d["key1"])
res = sorted(jobs, key=key)
print(res)
設定
jobs = [{"key1": "path/123", "key2": []}, \
{"key1": "path/12", "key2": []}, \
{"key1": "path/1", "key2": []}]
轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/366842.html
下一篇：在r中重組資料