如何在陣列子字串中搜索字串-有解無憂

我有一個這樣的陣列。如果陣列中的至少一個子字串具有我正在搜索的值，它應該通過。

Value1 = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside
]

使用打字稿，我試圖確保至少如果陣列中的子字串存在值 Food。即使這個 arrat 中的第三個子串沒有食物，它仍然應該通過。

到目前為止我已經嘗試過的代碼但沒有完成這項作業。它只回傳陣列

export function arraySubstring (expected:string, ignoreCase?: boolean): Expectation<string[], string> {
 return Expectation.that("test", expected, 
    async(actor: Actor, actual: string[]): Promise<boolean> ==> {

  try {
   for (const value of actual) {
     if(ignoreCase) {
       if (!value.toLowerCase().includes(expected.toLowerCase())) return 
         false;
     } else {
         if (!value.includes(expected)) return false;
     }
  }
  return true;
})
}

const value2= await webActor.attemptsTo(Ensure.that("my expectation", 
value1, arraySubstring ("Food")))

uj5u.com熱心網友回復：

您的代碼依賴于它的順序。如果回圈的第一個元素不包含“食物”，它將回傳 false。Return 陳述句總是退出函式。

我建議創建一個字串并使用來檢查第一次出現的索引indexOf("food")，類似的東西。

const array = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside",
];

const found = array
  .reduce((obj, entry) => obj.concat(entry))
  .toLocaleLowerCase()
  .indexOf("food");
if (found >= 0) {
  console.log("Array contains food");
} else {
  console.log("Array does not contain food");
}

如果你想迭代你需要回傳真實的情況，這將從你的代碼中洗掉順序的重要性。

const array = [
  "Grape | 100 |Food Catering Service",
  "Apple | 100,000m |Food Catering Service",
  "Water Melon | 100,000m |Catering Service Outside",
  "100,000m |Food Catering Service Outside",
];

const ignoreCase = true;
const expected = "Food";

const containsExptected = (_array) => {
  for (const value of _array) {
    if (ignoreCase) {
      if (value.toLowerCase().indexOf(expected.toLowerCase()) >= 0) return true
    } else {
      if (value.indexOf(expected) >= 0) return true;
    }
  }
  return false;
};

const found = containsExptected(array);
if (found) {
  console.log("Array contains food");
} else {
  console.log("Array does not contain food");
}

uj5u.com熱心網友回復：

這是檢查字串陣列中子字串匹配的單行代碼：

const value = ["Grape | 100 |Food Catering Service", "Apple | 100,000m |Food Catering Service", "Water Melon | 100,000m |Catering Service Outside", "100,000m |Food Catering Service Outside"]

const expected = "Food"
const ignoreCase = true
console.log(value.some(val => (ignoreCase ? val.toLowerCase().includes(expected.toLowerCase()) : val.includes(expected))))

轉載請註明出處，本文鏈接：https://www.uj5u.com/houduan/389474.html

標籤：javascript 数组打字稿

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