在我的管道中，我有兩個串列，想要比較它并相應地列印輸出
1- println abc
[aaa, bbb, ccc]
2- println xyz
[bbb, ccc]
我需要將輸出列印到一個檔案，如：
aaa not present in xyz
bbb present
ccc preset
我試過的代碼：
def test []
test = abc - xyz
println test
uj5u.com熱心網友回復：
def abc = ['aaa', 'bbb', 'ccc']
def xyz = ['bbb', 'ccc']
//simple
println 'present in xyz: ' abc.intersect(xyz).join(', ')
println 'not present in xyz: ' abc.minus(xyz).join(', ')
//with for-each
for(i in abc){
if(i in xyz) println "present in xyz: $i"
else println "not present in xyz: $i"
}
uj5u.com熱心網友回復：
您可以嘗試以下方法：
abc.each{valueOne ->
doesValueExist = false
xyz.each{ valueTwo->
if(valueOne.equals(valueTwo}{
doesValueExist = true
}
}
if(doesValueExist){
echo "${valueOne} is present"
} else {
echo "${valueOne} is not present"
}
}
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