我在 AWS 檔案中看到 ARN 格式是：
arn:partition:service:region:account-id:resource-id
arn:partition:service:region:account-id:resource-type/resource-id
arn:partition:service:region:account-id:resource-type:resource-id
我正在嘗試resource-id從 ARN 獲取。
以下代碼有效，但丑陋...
我正在尋找如何改進它：
func GetResourceNameFromARN(roleARN string) string {
if parsedARN, err := arn.Parse(roleARN); err == nil {
return parsedARN.Resource
}
return ""
}
func extractResourceId(arn string) string {
resource := GetResourceNameFromARN(arn)
switch len(strings.Split(resource, "/")) {
case 1:
switch len(strings.Split(resource, ":")) {
case 2:
return strings.Split(resource, ":")[1]
}
case 2:
return strings.Split(resource, "/")[1]
}
return resource
}
uj5u.com熱心網友回復：
我建議一個簡單的正則運算式：
package main
import (
"fmt"
"regexp"
)
func main() {
// Compile the expression once, usually at init time.
// Use raw strings to avoid having to quote the backslashes.
var validID = regexp.MustCompile(`[^:/]*$`)
fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-id"))
fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type/resource-id"))
fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type:resource-id"))
}
在此處查看演示
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