如何在多個物件中分解單個JSON物件

我是新手，如果我犯了任何錯誤，請原諒。

我正在從資料庫中讀取一行資料，我收到的資料是 JSON 物件，如下所示：

var details = {jan: '2591.00', feb: '4898.00', mar: '26290.00', apr: '22719.00', may: '26528.00',start: '2020', end: '2022', v1: '34', v2: '22'};

現在我想改變/修改這個 JSON 物件，使它看起來像這樣：

var details = [
{jan: '2591.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{feb: '4898.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{mar: '26290.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{apr: '22719.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{may: '26528.00',start: '2020', end: '2022', v1: '34', v2: '22'}

]

我的方法：我一直試圖通過使用來實作這一點：

result = Object
        .keys(details)
        .map(k => ({ [k]: details[k] }));

但是，它會在每個鍵值對處中斷。

var details = {jan: '2591.00', feb: '4898.00', mar: '26290.00', apr: '22719.00', may: '26528.00',start: '2020', end: '2022', v1: '34', v2: '22'};



var details = [
{jan: '2591.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{feb: '4898.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{mar: '26290.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{apr: '22719.00',start: '2020', end: '2022', v1: '34', v2: '22'},
{may: '26528.00',start: '2020', end: '2022', v1: '34', v2: '22'}

]

uj5u.com熱心網友回復：

let details = {
  jan: '2591.00',
  feb: '4898.00',
  mar: '26290.00',
  apr: '22719.00',
  may: '26528.00',
  start: '2020',
  end: '2022',
  v1: '34',
  v2: '22'
};
let months = ['jan', 'feb', 'mar', 'apr', 'may'];

let detailsByMonth = months.map(month => ({
  [month]: details[month],
  start: details.start,
  end: details.end,
  v1: details.v1,
  v2: details.v2
}));

console.log(detailsByMonth);

uj5u.com熱心網友回復：

這是一個班輪。首先，我根據您在陣列中不想要的內容過濾物件的鍵（也可以執行相反的操作）。然后我將它們映射到所需型別的物件中。

const mappedDetails = Object.keys(details)
    .filter((i) => !["v1", "v2", "start", "end"].includes(i))
        .map((j) => ({
            [j]: details[j], 
            start: details.start, 
            end: details.end, 
            v1: details.v1, 
            v2: details.v2
        })
    );

uj5u.com熱心網友回復：

嘗試這個

var arrContinue = ["start", "end", "v1", "v2"];
const newDetails = Object.keys(details)
  .filter(k => (arrContinue.indexOf(k) == -1))
  .map(k => ({
    [k]: details[k],
    start: details.start,
    end: details.end,
    v1: details.v1,
    v2: details.v2,
  }));

uj5u.com熱心網友回復：

代碼片段中添加了實作細節以更好地理解它。

// Input object
const details = {
  jan: '2591.00',
  feb: '4898.00',
  mar: '26290.00',
  apr: '22719.00',
  may: '26528.00',
  start: '2020',
  end: '2022',
  v1: '34',
  v2: '22'
};

// Create an array which contains only month names by using Object.keys() to get the keys array of details object and then filtered out start, end, v1 & v2 via Array.filter() method.
const monthsArray = Object.keys(details).filter((element) => !['start', 'end', 'v1', 'v2'].includes(element));

// Creating an array which contain objects with the month details by using Array.map() method.
const result = monthsArray.map((month) => ({
  [month]: details[month],
  start: details.start,
  end: details.end,
  v1: details.v1,
  v2: details.v2
}));

// Final Result.
console.log(result);

標籤：javascript json javascript 对象 数组合并

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