我已經嵌套了 JSON，我正在嘗試回傳一個物件并更新 UI。但是，我只能從Result陣列訪問屬性，但無法從AnalyzedInstactions訪問Step。
以下是在 JSON 中表示資料的類。使用https://app.quicktype.io生成它
import UIKit
class ResultArray: Codable {
var results = [Result]()
}
class Result: Codable, CustomStringConvertible {
var title: String = ""
var image = ""
var readyInMinutes: Int? = 0
var servings: Int? = 0
var cuisines = [String]()
var dishTypes = [String]()
var diets = [String]()
var occasions = [String]()
var analyzedInstructions = [AnalyzedInstruction]()
var description: String {
return "\nResults - Name: \(title), Summary: \(String(describing: readyInMinutes ?? nil)), \(String(describing: servings ?? nil)) "
}
}
// MARK: - Steps
class AnalyzedInstruction: Codable {
var name: String? = ""
var steps = [Step]()
}
class Step: Codable {
var number: Int = 0
var step: String = ""
}
這是我的決議方法
private func parse(data: Data) -> [Result] {
do {
let decoder = JSONDecoder()
let result = try decoder.decode(ResultArray.self, from: data)
return result.results
} catch {
print("JSON Error: \(error)")
return []
}
}
uj5u.com熱心網友回復：
試試這個簡單的代碼來從 AnalyzedInstructions 訪問你的步驟：
let results: [Result] = parse(data: theData)
if let firstResult = results.first {
if let firstAnaInst = firstResult.analyzedInstructions.first {
for step in firstAnaInst.steps {
print("--> step.step: \(step.step) step.number: \(step.number)")
}
} else { print(" NO analyzedInstructions") }
} else { print(" NO results") }
如果你想要所有步驟：
for result in results {
for anaInst in result.analyzedInstructions {
for step in anaInst.steps {
print("--> step.step: \(step.step) step.number: \(step.number)")
}
}
}
PS：如果合適，您可以考慮使用struct代替class您的 json 模型。
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