我試圖重命名這個陣列的鍵:
'oldname': [
{"name": "cat", "category": "animal"}
,{"name": "dog", "category": "animal"}
,{"name": "pig", "category": "animal"}
],
'oldname1': [
{"name": "pikachu", "category": "pokemon"}
,{"name": "Arbok", "category": "pokemon"}
,{"name": "Eevee", "category": "pokemon"}
]
我試過這段代碼:
const obj = {oldKey: Object.values(result)};
delete Object.assign(results, {newname: obj.oldKey})['oldname'];
console.log(result);
但我做錯了,因為我們不需要影響價值,它應該是這樣的:
'newname': [
{"name": "cat", "category": "animal"}
,{"name": "dog", "category": "animal"}
,{"name": "pig", "category": "animal"}
],
'newname1': [
{"name": "pikachu", "category": "pokemon"}
,{"name": "Arbok", "category": "pokemon"}
,{"name": "Eevee", "category": "pokemon"}
]
有沒有更好的方法來使用javascript?
uj5u.com熱心網友回復:
你可以使用Object.entries并Object.fromEntries做到這一點
const replaceKeys = (data, mapping) =>
Object.fromEntries(
Object.entries(data).map(([k, v]) => [mapping[k] || k, v])
)
const data1 = {
oldName1: 1,
oldName2: 2,
anotherKey: 3
}
const mapping = {
oldName1: 'newName1',
oldName2: 'newName2'
}
console.log(replaceKeys(data1, mapping))
uj5u.com熱心網友回復:
如果您不想創建新變數/陣列,可以使用for..of回圈,Object.entries()如下所示:
const
input = { 'oldname': [ {"name": "cat", "category": "animal"} ,{"name": "dog", "category": "animal"} ,{"name": "pig", "category": "animal"} ], 'oldname1': [ {"name": "pikachu", "category": "pokemon"} ,{"name": "Arbok", "category": "pokemon"} ,{"name": "Eevee", "category": "pokemon"} ] },
mapping = {'oldname':'newname','oldname1':'newname1'};
for(let [key,value] of Object.entries(input)) {
input[mapping[key]] = value;
delete input[key];
}
console.log( input );
否則,您可以按以下方式進行:
const
input = { 'oldname': [ {"name": "cat", "category": "animal"} ,{"name": "dog", "category": "animal"} ,{"name": "pig", "category": "animal"} ], 'oldname1': [ {"name": "pikachu", "category": "pokemon"} ,{"name": "Arbok", "category": "pokemon"} ,{"name": "Eevee", "category": "pokemon"} ] },
mapping = {'oldname':'newname','oldname1':'newname1','oldname2':'newname2','oldnamen':'newnamen'},
output = Object.fromEntries(
Object.entries(mapping).map(([oldname,newname]) => [newname, input[oldname]])
.filter(([,value]) => value)
);
console.log( input );
轉載請註明出處,本文鏈接:https://www.uj5u.com/houduan/463319.html
標籤:javascript 数组 json 多维数组
上一篇:有沒有辦法將`Try`鏈接為monad,同時也不會捕獲沿鏈引發的例外?
下一篇:使用深拷貝的陣列物件
