正如我的帖子標題所說，我正在嘗試創建一個類來解決數獨游戲，我想使用 OOP 樣式列印一個棋盤if name == "main":
我的輸出假設如下所示：
到目前為止，這是我的代碼：
class Sudoku:
def __init__(self):
self.board = [
[7, 8, 0, 4, 0, 0, 1, 2, 0],
[6, 0, 0, 0, 7, 5, 0, 0, 9],
[0, 0, 0, 6, 0, 1, 0, 7, 8],
[0, 0, 7, 0, 4, 0, 2, 6, 0],
[0, 0, 1, 0, 5, 0, 9, 3, 0],
[9, 0, 4, 0, 6, 0, 0, 0, 5],
[0, 7, 0, 3, 0, 0, 0, 1, 2],
[1, 2, 0, 0, 0, 7, 4, 0, 0],
[0, 4, 9, 2, 0, 6, 0, 0, 7]
]
def print_board(self, board) -> None:
for row in range(len(board)):
if row % 3 == 0 and row != 0:
print("- - - - - - - - - - - - - ")
for col in range(len(board[0])):
if col % 3 == 0 and col != 0:
print(" | ", end="")
if col == 8:
print(board[row][col])
else:
print(str(board[row][col]) " ", end="")
# Not sure if we need string representation of the board
# def __str__(self):
# return f"{self.board}"
if __name__ == "__main__":
sudoku = Sudoku()
sudoku.print_board(sudoku.board)
這是我從上面的代碼中得到的輸出：
先感謝您。
uj5u.com熱心網友回復：
問題是“列”回圈沒有嵌套在“行”回圈中，您的代碼應該如下所示：
class Sudoku:
def __init__(self):
self.board = [
[7, 8, 0, 4, 0, 0, 1, 2, 0],
[6, 0, 0, 0, 7, 5, 0, 0, 9],
[0, 0, 0, 6, 0, 1, 0, 7, 8],
[0, 0, 7, 0, 4, 0, 2, 6, 0],
[0, 0, 1, 0, 5, 0, 9, 3, 0],
[9, 0, 4, 0, 6, 0, 0, 0, 5],
[0, 7, 0, 3, 0, 0, 0, 1, 2],
[1, 2, 0, 0, 0, 7, 4, 0, 0],
[0, 4, 9, 2, 0, 6, 0, 0, 7]
]
def print_board(self, board) -> None:
for row in range(len(board)):
if row % 3 == 0 and row != 0:
print("- - - - - - - - - - - - - ")
for col in range(len(board[0])):
if col % 3 == 0 and col != 0:
print(" | ", end="")
if col == 8:
print(board[row][col])
else:
print(str(board[row][col]) " ", end="")
if __name__ == "__main__":
sudoku = Sudoku()
sudoku.print_board(sudoku.board)
uj5u.com熱心網友回復：
class Sudoku:
def __init__(self):
self.board = [
[7, 8, 0, 4, 0, 0, 1, 2, 0],
[6, 0, 0, 0, 7, 5, 0, 0, 9],
[0, 0, 0, 6, 0, 1, 0, 7, 8],
[0, 0, 7, 0, 4, 0, 2, 6, 0],
[0, 0, 1, 0, 5, 0, 9, 3, 0],
[9, 0, 4, 0, 6, 0, 0, 0, 5],
[0, 7, 0, 3, 0, 0, 0, 1, 2],
[1, 2, 0, 0, 0, 7, 4, 0, 0],
[0, 4, 9, 2, 0, 6, 0, 0, 7]
]
def print_board(self) -> None:
for index,a in enumerate(self.board):
a.insert(3,'|')
a.insert(7,'|')
print(*a)
if (index 1)%3==0 and len(self.board)-1>index:
print("-"*21)
if __name__ == '__main__':
sudoku = Sudoku()
sudoku.print_board()
輸出
7 8 0 | 4 0 0 | 1 2 0
6 0 0 | 0 7 5 | 0 0 9
0 0 0 | 6 0 1 | 0 7 8
---------------------
0 0 7 | 0 4 0 | 2 6 0
0 0 1 | 0 5 0 | 9 3 0
9 0 4 | 0 6 0 | 0 0 5
---------------------
0 7 0 | 3 0 0 | 0 1 2
1 2 0 | 0 0 7 | 4 0 0
0 4 9 | 2 0 6 | 0 0 7
uj5u.com熱心網友回復：
你可以看看py-sudoku__format_board_ascii中的方法。
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