在我的 Python 代碼中，我試圖讓用戶從列印的串列中輸入其中一個作業系統，然后讓演算法在指定的元組中吐出它的索引。但是，即使我從串列中輸入作業系統，它也會回傳我所做的錯誤訊息：
“下次請從串列中選擇一個選項。”
我能做些什么來解決這個問題？
下面是代碼：
print("""Operating systems available:
Windows 10
Linux Mint
Mac OS 11
Android Oreo
Android Pie
Android 11
iOS 14
""")
desired_string = input("From the above list, what operating system would you like to use?: ")
my_tuple = ["Windows 10", "Linux Mint", "Mac OS 11", "Android Oreo", "Android Pie", "Android 11", "iOS 14"]
def linear_search(desired_string, my_tuple):
for each_item_index in range(len(my_tuple)):
if desired_string == my_tuple[each_item_index]:
return each_item_index
return -1
if desired_string != ("Windows 10", "Linux Mint", "Mac OS 11", "Android Oreo", "Android Pie", "Android 11", "iOS 14"):
print("please select an option from the list next time.")
quit()
else:
search = linear_search(desired_string, my_tuple)
print(search)
uj5u.com熱心網友回復：
決定使用這個，
if desired_string != ("Windows 10", "Linux Mint", "Mac OS 11", "Android Oreo", "Android Pie", "Android 11", "iOS 14"):
print("please select an option from the list next time.")
quit()
!= 它檢查值和資料型別。在上述情況下是 (string != tuple) 這是真的
用這個，
if desired_string not in ("Windows 10", "Linux Mint", "Mac OS 11", "Android Oreo", "Android Pie", "Android 11", "iOS 14"):
print("please select an option from the list next time.")
quit()
in關鍵字用于檢查串列/元組中的元素是否存在，如果它存在則回傳 True，否則回傳 False。
如果元素存在，則not in it 與in成反比，則回傳 False。如果元組/串列中不存在該元素，則回傳 True
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