我的資料框如下所示：
variations_list1 variations_list2
["yellow","ornage"] []
["xl","xxl"] []
["Burger","pizza"] ["$25","$30"]
預期資料框：
variations_list1 variations_list2
["yellow","ornage"] ["yellow","ornage"] #filling emty list with current row data
["xl","xxl"] ["xl","xxl"]
["Burger","pizza"] ["$25","$30"]
uj5u.com熱心網友回復：
你可以做
df.loc[~df['variations_list2'].astype(bool),'variations_list2'] = df['variations_list1']
你有和以前一樣的問題，串列不是串列
df.loc[df['variations_list2']=='[]','variations_list2'] = df['variations_list1']
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標籤：Python python-3.x 熊猫
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