org.springframework.orm.jpa.JpaSystemException：不要更改對啟用了delete-orphan的集合的參考

我正在使用彈簧資料 jpa。當我想克隆一個具有一對多關系的物體時，

    fun clonePurchaseOrder(purchaseOrder: PurchaseOrder, operator: String): PurchaseOrder {
        //prepare data
        val items = purchaseOrder.items
        //detach
        items.forEach { entityManager.detach(it) }
        purchaseOrder.costRevise?.let { entityManager.detach(it) }
        entityManager.detach(purchaseOrder)
        purchaseOrder.id = null
        //modify
        items.forEach {
            it.id = null
            it.purchaseOrder = purchaseOrder
        }     
        //modify purchaseOrder
        val now = Date()
        return purchaseOrder.apply {
            number = null
            costRevise = null
            paymentHistories = mutableListOf()
            status = PurchaseOrder.Status.DRAFT
            createTime = now
            creator = operator
            modifyTime = now
            submitTime = null
            submitOperator = null
            closeOperator = null
            closeReason = null
            closeTime = null
        }.save()
    }

我設定purchaseOrder id = null，并且每個專案id = null，但得到以下例外

org.springframework.orm.jpa.JpaSystemException: Don't change the reference to a collection with delete-orphan enabled : com.hkmci.web.bms2.backend.database.entity.PurchaseOrder.items; nested exception is org.hibernate.HibernateException: Don't change the reference to a collection with delete-orphan enabled : com.hkmci.web.bms2.backend.database.entity.PurchaseOrder.items

這里是 purchaseOrder 物體和 items 物體

@Entity
class PurchaseOrder(
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    var id: Long? = null,

    ...(other Column)

    @OneToMany(mappedBy = "purchaseOrder", cascade = [CascadeType.ALL], orphanRemoval = true)
    var items: MutableList<PurchaseOrderItem> = mutableListOf(),

    ...(other Column)

@Entity
class PurchaseOrderItem(
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    var id: Long? = null,

    @ManyToOne(fetch = FetchType.LAZY)
    var purchaseOrder: PurchaseOrder,

    ...(other column)

有人能幫忙嗎？

uj5u.com熱心網友回復：

//clone a purchaseOrder, new purchaseOrder will be reset to Draft
    fun clonePurchaseOrder(purchaseOrder: PurchaseOrder, operator: String): PurchaseOrder {
        //clear all relationships
        purchaseOrder.costRevise?.let { entityManager.detach(it) }
        purchaseOrder.items.forEach {
            entityManager.detach(it)
            it.id = null
        }
        purchaseOrder.paymentHistories.forEach {
            entityManager.detach(it)
        }
        entityManager.detach(purchaseOrder)
        //reset all fields
        val now = Date()
        purchaseOrder.apply {
            id = null
            number = null
            costRevise = null
            items = items.toMutableList()
            paymentHistories = mutableListOf()
            status = PurchaseOrder.Status.DRAFT
            createTime = now
            creator = operator
            modifyTime = now
            submitTime = null
            submitOperator = null
            closeOperator = null
            closeReason = null
            closeTime = null
        }
        //save
        return purchaseOrderRepository.save(purchaseOrder)
    }

無需重新關聯 items 和 purchaseOrder ，只需清除所有關系，設定 id = null 并保存

標籤：爪哇 春天 休眠 jpa

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