有沒有辦法在Listview上進行雙擊事件并將串列資料發送到XamarinForms中的另一個頁面

這就是我現在所做的，我無法發送ID到另一個頁面。并且命令引數有一個錯誤作為空參考例外。

xml:

 <ListView x:Name="studentListView" ItemsSource="{Binding .} "> 
                    <ListView.ItemTemplate >
                        
                        <DataTemplate  >
                            <ViewCell>
                                <StackLayout Orientation="Horizontal">
                                    <Label Text="{Binding StudentID}"></Label>
                                    <Label Text="{Binding FirstName}"></Label>
                                    <Label Text="{Binding LastName}"></Label>
                                    <Label Text="{Binding Gender}"></Label>
                                    <Label Text="{Binding Age}"></Label>
                                    <Label Text="{Binding Class}"></Label>
                                    <StackLayout.GestureRecognizers>
                                        <TapGestureRecognizer NumberOfTapsRequired="1" Tapped="TapGestureRecognizer_Tapped" CommandParameter="{Binding StudentID}"/>
                                        <TapGestureRecognizer NumberOfTapsRequired="2" Tapped="TapGestureRecognizer_Tapped_1"/>
                                    </StackLayout.GestureRecognizers>
                                </StackLayout>
                            </ViewCell>
                        </DataTemplate>
                    </ListView.ItemTemplate>
                </ListView>

C#代碼如下：

private void TapGestureRecognizer_Tapped(object sender, EventArgs e)
        {
       TapGestureRecognizer tapGesture = sender as TapGestureRecognizer;
            int clubid = (int) tapGesture.CommandParameter;
            Navigation.PushAsync(new StudentPage(clubid));
        }

uj5u.com熱心網友回復：

您也可以直接TapGestureRecognizer在StudentID上添加一個Label，然后獲取 ID 值以將其發送到另一個 Page。以下是供您參考的代碼：

學生頁面 Xaml：

    <ListView x:Name="studentListView" > 
                <ListView.ItemTemplate>
                    <DataTemplate>
                        <ViewCell>
                            <StackLayout Orientation="Horizontal">
                                <Label Text="{Binding StudentID}" WidthRequest="100" >
                                    <Label.GestureRecognizers  >
                                        <TapGestureRecognizer NumberOfTapsRequired="2" Tapped="TapGestureRecognizer_Tapped">
                                        </TapGestureRecognizer>
                                    </Label.GestureRecognizers>
                                </Label>
                                <Label Text="{Binding FirstName}"/>
                            </StackLayout>
                        </ViewCell>
                    </DataTemplate>
                </ListView.ItemTemplate>
            </ListView>

后端代碼：

     public StudentList() 
        {

            InitializeComponent();

            studentListView.ItemsSource = new List<MyStudent>
            {

                new MyStudent{StudentID="1", FirstName="Steve"},
                new MyStudent{StudentID="2", FirstName="Lorence"}
            };
        }

        private void TapGestureRecognizer_Tapped(object sender, EventArgs e)
        {
           //get the StudentID and pass it through constructor
            var s = (sender as Label).Text;
            Navigation.PushModalAsync(new MainPage(s));
        }

然后，在另一個頁面中獲取StudentIDvia建構式。

  public MainPage(string a)
  {
       InitializeComponent();

       App.Current.MainPage.DisplayAlert("Student Id is", a, "OK");
  }

標籤：C＃网xmlxamarinxamarin.forms

上一篇：.NetMAUIWebViewwithiFrame-視窗高度問題

下一篇：使用XAMLSetter設定自定義附加屬性