{
"code":200,
"msg":"success",
"newslist":[
{
"content":"顯示標題Admin",
"source":"顯示名字User"
}
]
}
請問這個怎么獲取"content"和"source"
JSON Ajax 都可以
謝謝各位大神解答。萬分感謝。
uj5u.com熱心網友回復:
var res = {"code":200,
"msg":"success",
"newslist":[
{
"content":"顯示標題Admin",
"source":"顯示名字User"
}
]
};
var content = res.newlist[0].content;
var source = res.newlist[0].source;
轉載請註明出處,本文鏈接:https://www.uj5u.com/qianduan/218981.html
標籤:Ajax
