例如：<select class="editSelect_SeverId" id="editSelect_SeverId" name="select_server_address" data-width="150px" οnchange="serverIdChange();"></select>
AJAX回傳值給上面的下拉框后，樣式沒出現，修復如下：
$.ajax({
type: 'get',
url: getServerIpListUrl,
dataType: "json",
success: function (data) {
var item = data.serverIpList;
var state = data.result;
if (state == '1') {
for (var i = 0; i < item.length; i++) {
if (i == 0) {
$("#select_severId").append("<option value='" + item[i].serverId + "' selected>" + item[i].serverIp + "</option>");
$("#editSelect_SeverId").append("<option value='" + item[i].serverId + "' selected>" + item[i].serverIp + "</option>");
} else {
$("#select_severId").append("<option value='" + item[i].serverId + "'>" + item[i].serverIp + "</option>");
$("#editSelect_SeverId").append("<option value='" + item[i].serverId + "'>" + item[i].serverIp + "</option>");
}
}
}
$('#editSelect_SeverId').select2({data: item});
}
});
很明顯，回傳的資料用：$('#editSelect_SeverId').select2({data: item});形式處理下就OK了
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