我試圖用 Django RestFramework 創建一個 API，所以我創建了 2 個模型 Note 和 Task，并在 Note 模型中有一個 ManyToManyField，所以我可以在 Note 中放置許多任務，但我創建的 API 不回傳完整的物件功能，而只回傳 id . 這是我的代碼：
class NoteAPI(ListAPIView):
serializer_class = NoteSerializer
queryset = Note.objects.all()
這是我的模型：
class Task(models.Model):
task = models.CharField(max_length=255, null=False, blank=False)
detail = models.CharField(max_length=255, null=True, blank=True)
completed = models.BooleanField(default=False)
priority = models.IntegerField(default=0)
def __str__(self):
return self.task
class Note(models.Model):
title = models.CharField(max_length=255, null=False, blank=False)
priority = models.CharField(max_length=1, choices=PRIORITY_CHOICES, default="B")
detail = models.CharField(max_length=255, null=True, blank=True)
completed = models.BooleanField(default=False)
task = models.ManyToManyField(Task, related_name="note_task", blank=True)
process = models.IntegerField( default=0, validators=[max_int_value])
def __str__(self) -> str:
return self.title " is " str(self.process) "% completed"
我希望輸出罐看起來像：
[
{
"id": 2,
"title": "Sleep",
"priority": "F",
"detail": "Don't do it, stay awake and do your job",
"completed": false,
"process": 0,
"task": [
{
"id": 1,
"task": "Go to bed",
"completed": false
},
{
"id": 2,
"task": "Start counting",
"completed": false
}
]
}
]
但實際上是這樣的
[
{
"id": 2,
"title": "Sleep",
"priority": "F",
"detail": "Don't do it, stay awake and do your job",
"completed": false,
"process": 0,
"task": [
1,
2
]
}
]
那么我能做些什么來得到這樣的輸出呢？
uj5u.com熱心網友回復：
您需要告訴NoteSerializer如何序列化Taskobjectcs。
class TaskSerializer(serializers.ModelSerializer):
class Meta:
model = Task
fields = ("id", "task", "completed")
class NoteSerializer(models.Model):
task = TaskSerializer(many=True)
您可能還希望預取任務以將資料庫查詢的數量保持在最低限度。
class NoteAPI(ListAPIView):
serializer_class = NoteSerializer
queryset = Note.objects.prefetch_related("task").all()
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標籤：Python json 姜戈 列表 Django 休息框架