為什么在嘗試訪問HTML表中的前兩列時出現錯誤？

import requests
from bs4 import BeautifulSoup

wiki = "https://en.wikipedia.org/wiki/List_of_Pixar_films"
website_url = requests.get(wiki).text
soup = BeautifulSoup(website_url, 'lxml')
table_class = "wikitable plainrowheaders sortable"
my_table = soup.find('table', {'class': table_class})


Film = []
release = []

for row in my_table.find_all('i')[0:]:
    Film_cell = row.find_all('a')[0]
    Film.append(Film_cell.text)
print(Film)

for row in my_table.find_all('td')[0:]:
    release = row.find_all('span')[:1]
    release.append(release.text)
print(release)

輸出：

['Toy Story', "A Bug's Life", 'Toy Story 2', 'Monsters, Inc.',
'Finding Nemo', 'The Incredibles', 'Cars', 'Ratatouille', 'WALL-E',
'Up', 'Toy Story 3', 'Cars 2', 'Brave', 'Monsters University', 'Inside Out',
'The Good Dinosaur', 'Finding Dory', 'Cars 3', 'Coco', 'Incredibles 2',
'Toy Story 4', 'Onward', 'Soul', 'Luca', 'Turning Red', 'Lightyear']
---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-223-6481bc092354> in <module>
      7 for row in my_table.find_all('td')[0:]:
      8     release = row.find_all('span')[:1]
----> 9     release.append(release.text)
     10 print(release)

AttributeError: 'list' object has no attribute 'text'

uj5u.com熱心網友回復：

for row in my_table.find_all('td')[0:]:
    release= row.find_all('span')[:1]
    release.append(release.text)
print(release)

• my_table.find_all('td')[0:] 與 my_table.find_all('td')
• row.find_all('span')[:1] 是一個串列，可能是 row.find_all('span')[0]
• release= row.find_all('span')[:1], 應該使用另一個變數

獲取前兩列，不包括索引列。

release = []
for row in my_table.find_all('td'):
    span = row.find_all('span')
    if span:
        release.append(span[0].text)
print(release)

[('Toy Story', 'November 22, 1995'), ("A Bug's Life", 'November 25, 1998'), ('Toy Story 2', 'November 24, 1999'), ('Monsters, Inc.', 'November 2, 2001'), ('Finding Nemo', 'May 30, 2003'), ('The Incredibles', 'November 5, 2004'), ('Cars', 'June 9, 2006'), ('Ratatouille', 'June 29, 2007'), ('WALL-E', 'June 27, 2008'), ('Up', 'May 29, 2009'), ('Toy Story 3', 'June 18, 2010'), ('Cars 2', 'June 24, 2011'), ('Brave', 'June 22, 2012'), ('Monsters University', 'June 21, 2013'), ('Inside Out', 'June 19, 2015'), ('The Good Dinosaur', 'November 25, 2015'), ('Finding Dory', 'June 17, 2016'), ('Cars 3', 'June 16, 2017'), ('Coco', 'November 22, 2017'), ('Incredibles 2', 'June 15, 2018'), ('Toy Story 4', 'June 21, 2019'), ('Onward', 'March 6, 2020'), ('Soul', 'December 25, 2020'), ('Luca', 'June 18, 2021'), ('Turning Red[1]', 'March 11, 2022[5]'), ('Lightyear[2]', 'June 17, 2022[5]'), ('TBA', 'June 16, 2023[8]'), ('TBA', 'March 1, 2024[4]'), ('TBA', 'June 14, 2024[4]')]

uj5u.com熱心網友回復：

該代碼release= row.find_all('span')[:1]生成一個沒有“文本”引數的串列。您需要進一步決議它以獲取“文本”元素，即release.append(release[0].text)代替release.append(release.text).

但這也會產生“索引越界錯誤”，因為回圈中的許多串列都是空的。

修改后的代碼如下：

import requests
from bs4 import BeautifulSoup
wiki = "https://en.wikipedia.org/wiki/List_of_Pixar_films"
website_url = requests.get(wiki).text
soup = BeautifulSoup(website_url,'lxml')
table_class = "wikitable plainrowheaders sortable"
my_table = soup.find('table',{'class':table_class})


Film = []
release = []

for row in my_table.find_all('i')[0:]:
    Film_cell = row.find_all('a')[0]
    Film.append(Film_cell.text)
print(Film)

new_list = []
for row in my_table.find_all('td')[0:]:
    release= row.find_all('span')[:1]    
    if len(release) > 0:
        new_list.append(release[0].text)
    print(new_list)

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