我正在嘗試列印系列，但每當我將范圍（我給出的輸入）設定為 407 以上時。我只能得到輸出直到 407。但是，當我將范圍設定為低于 407 時，它會根據我的輸入給出結果給定的。誰能告訴我我做錯了什么？
我使用在線編譯器 ( www.onlinegdb.com ) 來撰寫我的代碼。
這是代碼。
#include<stdio.h>
#include<stdlib.h>
int
main ()
{
int m, n;
printf
("Enter two numbers to find the Armstrong numbers that lie between them.\n");
scanf ("%d%d", &m, &n);
system("clear");
if(m>n)
{
m = m n;
n = m - n;
m = m - n;
}
for (; m < n; m )
{
int i = m 1, r, s = 0, t;
t = i;
while (i > 0)
{
r = i % 10;
s = s (r * r * r);
i = i / 10;
}
if (t == s)
printf ("%d ", t);
}
return 0;
}
在此處輸入圖片說明
在此處輸入圖片說明
uj5u.com熱心網友回復：
Try this code!!!
#include <math.h>
#include <stdio.h>
int main() {
int low, high, number, originalNumber, rem, count = 0;
double result = 0.0;
printf("Enter two numbers(intervals): ");
scanf("%d %d", &low, &high);
printf("Armstrong numbers between %d and %d are: ", low, high);
// swap numbers if high < low
if (high < low) {
high = low;
low = high - low;
high -= low;
}
// iterate number from (low 1) to (high - 1)
// In each iteration, check if number is Armstrong
for (number = low 1; number < high; number) {
originalNumber = number;
// number of digits calculation
while (originalNumber != 0) {
originalNumber /= 10;
count;
}
originalNumber = number;
// result contains sum of nth power of individual digits
while (originalNumber != 0) {
rem = originalNumber % 10;
result = pow(rem, count);
originalNumber /= 10;
}
// check if number is equal to the sum of nth power of individual digits
if ((int)result == number) {
printf("%d ", number);
}
// resetting the values
count = 0;
result = 0;
}
return 0;
}
uj5u.com熱心網友回復：
試試這個代碼：
#include <stdio.h>
#include <math.h>
int main()
{
int start, end, i, temp1, temp2, remainder, n = 0, result = 0;
printf(“Enter start value and end value : “);
scanf(“%d %d”, &start, &end);
printf(“\nArmstrong numbers between %d an %d are: “, start, end);
for(i = start 1; i < end; i)
{
temp2 = i;
temp1 = i;
while (temp1 != 0)
{
temp1 /= 10;
n;
}
while (temp2 != 0)
{
remainder = temp2 % 10;
result = pow(remainder, n);
temp2 /= 10;
}
if (result == i) {
printf(“%d “, i);
}
n = 0;
result = 0;
}
printf(“\n”);
return 0;
}
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