如果它包含所需的值，我正在嘗試獲取串列的名稱（型別串列）：
def f(Value):
a = ['a','b','c']
b = ['d','e','f']
d = ['g','h','i']
c = ['j','k','l']
w = next(n for n,v in filter(lambda t: isinstance(t[1],list), locals().items()) if value in v)
return(w)
f()
好吧，這段代碼將回傳串列的名稱，但輸入字串，所以我以后將無法使用它。先感謝您
uj5u.com熱心網友回復：
您的代碼中有幾個錯誤 - 如果您想要串列，則回傳它而不是它的名稱：
def f(value): # capitalization not correct
a = ['a','b','c']
b = ['d','e','f']
d = ['g','h','i']
c = ['j','k','l']
# set w to v not n - n is the local name, v is the value
w = next(v for n,v in filter(lambda t: isinstance(t[1],list),
locals().items()) if value in v)
return w
# needs to be called with parameter
what_list = f("h")
print( what_list )
輸出：
['g', 'h', 'i']
我不明白為什么locals().items()在這個最小的例子中使用，你可以這樣做
for li in [a,b,c,d]: # simply add more lists if needed, no need to inspect locals
if value in li:
return li
反而。
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