Nestjsmongoose單元測驗：TypeError:<functionName>不是函式

根據這個github repo，我們要測驗一個用戶樣本，
考慮這個測驗檔案：

const mockUser = (
  phone = '9189993388',
  password = 'jack1234',
  id = '3458',
): User => ({
  phone,
  password,
  _id: new Schema.Types.ObjectId(id),
});

const mockUserDoc = (mock?: Partial<User>): Partial<IUserDocument> => ({
  phone: mock?.phone || '9189993388',
  password: mock?.password || 'jack1234',
  _id: mock?._id || new Schema.Types.ObjectId('3458'),
});

const userArray = [
  mockUser(),
  mockUser('Jack', '9364445566', '[email protected]'),
];

const userDocArray = [
  mockUserDoc(),
  mockUserDoc({
    phone: '9364445566',
    password: 'jack1234',
    _id: new Schema.Types.ObjectId('342'),
  }),
  mockUserDoc({
    phone: '9364445567',
    password: 'mac$',
    _id: new Schema.Types.ObjectId('425'),
  }),
];

describe('UserRepository', () => {
  let repo: UserRepository;
  let model: Model<IUserDocument>;

  beforeEach(async () => {
    const module: TestingModule = await Test.createTestingModule({
      providers: [
        UserRepository,
        {
          provide: getModelToken('User'),
          // notice that only the functions we call from the model are mocked
          useValue: {
            new: jest.fn().mockResolvedValue(mockUser()),
            constructor: jest.fn().mockResolvedValue(mockUser()),
            find: jest.fn(),
            findOne: jest.fn(),
            update: jest.fn(),
            create: jest.fn(),
            remove: jest.fn(),
            exec: jest.fn(),
          },
        },
      ],
    }).compile();

    repo = module.get<UserRepository>(UserRepository);
    model = module.get<Model<IUserDocument>>(getModelToken('User'));
  });

  it('should be defined', () => {
    expect(repo).toBeDefined();
  });

  afterEach(() => {
    jest.clearAllMocks();
  });

  it('should return all users', async () => {
    jest.spyOn(model, 'find').mockReturnValue({
      exec: jest.fn().mockResolvedValueOnce(userDocArray),
    } as any);
    const users = await repo.findAll({});
    expect(users).toEqual(userArray);
  });

  it('should getOne by id', async () => {
    const userId = '324';
    jest.spyOn(model, 'findOne').mockReturnValueOnce(
      createMock<Query<IUserDocument, IUserDocument>>({
        exec: jest.fn().mockResolvedValueOnce(
          mockUserDoc({
            _id: new Schema.Types.ObjectId(userId),
          }),
        ),
      }) as any,
    );
    const findMockUser = mockUser('Tom', userId);
    const foundUser = await repo.findById(new Schema.Types.ObjectId(userId));
    expect(foundUser).toEqual(findMockUser);
  });

這是用戶檔案檔案：

export interface IUserDocument extends Document {
  _id: Schema.Types.ObjectId;
  email?: string;
  password: string;
  firstName?: string;
  lastName?: string;
  nationalCode?: string;
  phone: string;
  address?: string;
  avatar?: string;
}

第一次和第二次測驗通過但第三次拋出：

TypeError: this.userModel.findById is not a function 介面也是從貓鼬檔案擴展而來findById的，測驗中無法識別該功能。

這是可用的 github 存盤庫。所以任何幫助將不勝感激。

uj5u.com熱心網友回復：

請注意，在您的UserModel模擬中，您如何不提供模擬功能findById

{
  provide: getModelToken('User'),
  // notice that only the functions we call from the model are mocked
  useValue: {
    new: jest.fn().mockResolvedValue(mockUser()),
    constructor: jest.fn().mockResolvedValue(mockUser()),
    find: jest.fn(),
    findOne: jest.fn(),
    update: jest.fn(),
    create: jest.fn(),
    remove: jest.fn(),
    exec: jest.fn(),
    findById: jest.fn(), // <-------------- Add this
  },
},

findById在您模擬的那組方法中需要有一個方法。

標籤：单元测试 猫鼬 开玩笑的 巢穴

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