通過函式更改熊貓資料框中的布林值

我對編碼和嘗試將 pandas df 中的布爾集從 True 更改為 False 非常陌生。我想根據名稱選擇某一行。我的 df，df_contacts 看起來像這樣：

     name  gender relationship category access          timestamp proof
0    Emma  female         ex-girlfriend   True  1653939064.769388     1 
1   Amber  female         ex-girlfriend   True  1653939064.769388     1 
2    Mark    male              business  False  1653939064.769388     1 
3  Claire  female         ex-girlfriend   True  1653939064.769388     1 
4    Sara  female             co-worker  False  1653939064.769388     1 
5  Marcus    male                friend  False  1653939064.769388     1 
6  George    male          soccer-coach  False  1653939064.769388     1

我想將 Emma 名字后面的 True 值更改為 False。如何根據 user_input 而不是索引撰寫此函式？

我被困在這個： code

block = str(input('Confirm restricting this contact from seeing your photos? '))
def switch_access (name):
        if block == 'yes':
            df_contacts.loc[df_contacts["access"] == True, False]
        print(df_contacts)

switch_access(name)

uj5u.com熱心網友回復：

這將使用 numpy 更改它

import numpy as np
block = str(input('Confirm restricting this contact from seeing your photos? '))
def switch_access (name):
        if block.lower() == 'yes':
            condition_list = [df_contacts['category'] == True, df_contacts['category'] == False]
            choice_list = [False, True]
            df_contacts['category'] = np.where(df_contacts['name'] == name, np.select(condition_list, choice_list, df_contacts['category']), df_contacts['category'])
        return df_contacts

df = switch_access('Emma')
df

我還稍微修改了您的代碼，使其更容錯

uj5u.com熱心網友回復：

您可以使用：

block = str(input('Confirm restricting this contact from seeing your photos? '))
def switch_access (name):
        if block == 'yes':
            df_contacts.loc[df_contacts['name'] == name, 'access'] = False
        print(df_contacts)

switch_access('Emma')

輸出：

     name  gender relationship category  access     timestamp  proof
0    Emma  female         ex-girlfriend   False  1.653939e 09      1  # True to False
1   Amber  female         ex-girlfriend    True  1.653939e 09      1
2    Mark    male              business   False  1.653939e 09      1
3  Claire  female         ex-girlfriend    True  1.653939e 09      1
4    Sara  female             co-worker   False  1.653939e 09      1
5  Marcus    male                friend   False  1.653939e 09      1
6  George    male          soccer-coach   False  1.653939e 09      1

uj5u.com熱心網友回復：

如果您想在更改布林值的同時讀取名稱，可以使用此代碼...

name = input("Enter name of contact: ")
block = str(input('Confirm restricting this contact from seeing your photos? ')) 
def switch_access(name, block): 
    if block.lower() == 'yes': 
        if df_contacts.loc[df_contacts["name"] == name]['access'][0] == True:
            df_contacts.loc[df_contacts["name"] == name, 'access'] = False
            print(df_contacts.loc[df_contacts["name"] == name])
            
switch_access(name, block)

輸出

Enter name of contact: Emma
Confirm restricting this contact from seeing your photos? Yes
   name  gender relationship_category  access     timestamp  proof
0  Emma  female         ex-girlfriend   False  1.653939e 09      1

標籤：Python 熊猫 功能 条件语句 布尔值

上一篇：有什么方法可以獲取公會的通知設定嗎？

下一篇：在python中不使用條件運算子的最大和最小數字